MCAT RT S.H.M 2022

MCAT RT S.H.M 2022

University

10 Qs

quiz-placeholder

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MCAT RT S.H.M 2022

MCAT RT S.H.M 2022

Assessment

Quiz

Physics

University

Easy

NGSS
HS-PS4-1, HS-PS3-2, HS-PS2-1

+1

Standards-aligned

Created by

Azfar haque

Used 21+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The force applied on a body attached with a spring is directly proportional to the

Amplitude

Displacement

A & B Both

None of These

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If a given spring of spring constant K is cut into three identical segments, the spring constant of each segment is

k2\frac{k}{2}

k3\frac{k}{3}

3k

4k

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A sound wave of frequency 400 Hz is travelling in air at a speed of 320 m/s. The wave length of the wave is

400 m

0.8 m

320 m

1.25 m

Tags

NGSS.HS-PS4-1

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

At mean position during S.H.M.

PE is max & KE is min

PE is min & KE is max

Both PE & KE are max

Both PE & KE are min

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The type of vibratory motion whose instantaneous acceleration at any distance x from the mean position is proportional to x and always directed towards the mean position is called

Simple harmonic motion

Torque

Oscillatory motion

None of these

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The instantaneous velocity of mass attached to spring having amplitude x0 executing SHM is

vo = xo1 x2x02v_{o\ }=\ x_o\sqrt{1\ -\ \frac{x^2}{x_0^2}}

vo = xokm1 + x2x02v_{o\ }=\ x_o\sqrt{\frac{k}{m}}\sqrt{1\ +\ \frac{x^2}{x_0^2}}

vo = xokm1 x2x02v_{o\ }=\ x_o\sqrt{\frac{k}{m}}\sqrt{1\ -\ \frac{x^2}{x_0^2}}

vo = xokm1 + x2x0v_{o\ }=\ x_o\sqrt{\frac{k}{m}}\sqrt{1\ +\ \frac{x^2}{x_0}}

Tags

NGSS.HS-PS3-2

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The time period of simple pendulum depends upon

The time period of simple pendulum depends upon

Material of the pendulum

Mass of the thread

Length of the pendulum

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