Solving Equations and Algebraic Proofs Review

• Subtract 6.00b from both sides of the equation

• Subtract 3.50b from both sides of the equation

• Subtract 400 from both sides of the equation

• Add 6.00b and 3.50b

Tags

CCSS.6.EE.B.7

• Add 7 to both sides of the equation

• Divide both sides of the equation by 3

• Subtract 7 from both sides of the equation

• Multiply both sides of the equation by 3

Tags

CCSS.7.EE.B.4A

Karen solve an equation incorrectly as shown below.

Given: 4(x + 1) - 3(x -2) = 11

Step 1: 4x + 4 - 3x + 6 = 11

Step 2: 4x - 3x + 4 + 6 = 11

Step 3: x + 10 = 11

Step 4: x + 10 + 10 = 11 + 10

Answer: x = 21

• From given to step 1

• From step 1 to step 2

• From step 2 to step 3

• From step 3 to step 4

Tags

CCSS.HSA.REI.A.1

Jared solved the equation shown below.

Given: 5(x + 1) - 3(x -2) = 13

Step 1: 5x + 5 - 3x + 6 = 13

Step 2: 5x - 3x + 5 + 6 = 13

Step 3: 2x + 11 = 13

Step 4: 2x + 11 - 11 = 13 - 11

Step 5: 2x = 2

Answer: x = 1

Which properties did he apply from step 1 to step 2?

• Associative pro

• Distributive property

• Subtraction property

• Commutative property

Tags

CCSS.HSA.REI.A.1

• S1: Mult. poe

  S2: Add. poe

  S3: CLT

  S4: Division poe

• S1: Distributive prop

  S2: Subtract. poe

  S3: Add. poe

  S4: Division poe

• S1: Distributive prop

  S2: Add. poe

  S3: Subtract. poe

  S4: Division poe

• S1: Mult. poe

  S2: Subtract. poe

  S3: CLT

  S4: Division poe

Tags

CCSS.6.EE.A.3

• I, II, III

• III, I, II

• III, II, I

• I, III, II

Tags

CCSS.HSA.REI.A.1

What is step 6

• Subtraction property of equality
• Addition property of equality
• Division property of equality

Tags

CCSS.HSA.REI.A.1

Find the error

• Adding 2x to 3x

• Subtracting 5 from both sides

• Adding 2x to -2x

• Dividing by 5 on both sides

Tags

CCSS.HSA.REI.A.1