Parabolas in Conic Form

A parabola is the set of all points equidistant from the focus and the directrix.

• true
• false

What is the point inside the parabola 'p' units from the vertex?

• vertex
• focus
• directrix
• axis of symmetry

The focus is always inside the parabola.

• true
• false

If the directrix is y = 4 and the focus is at 
(3, 0), the value of p is:

• 8
• -8
• 2
• -2

What is the directrix of this parabola?

• x = -3

• y = -3

• x = 3

• y = 3

What is the equation of this parabola?

• (y-1)² = -4(x-3)
• (y-1)²= 4(x+3)
• (y+1)² = 4(x-3)
• (y+1)² = -4(x+3)

Which of the following is the correct equation for the given graph?

• (x + 2)² = (y + 1)

• (x - 2)² = (y + 1)

• (x + 2)2 = -(y + 1)

• (x - 2)2 = -(y + 1)

Find the equation of the parabola with vertex (5,1) and Focus (2,1).

• $(y-1)^2=12(x-5)$

• $(y+1)^2=-12(x+5)$

• $(y-1)^2=-12(x-5)$

• $(x-5)^2=-12(y-1)$

Find the equation of the parabola with focus at (4, 5) and a directrix of x = 1.

• $(y-5)^2=6(x-5/2)$

• $(x-4)^2=8(y-3)$

• $(x+4)^2=8(y+3)$

• $(x-4)^2=-8(y-3)$

Tags

CCSS.HSG.GPE.A.2

Use the information provided to write the general equation of the parabola with focus at (5, 2) and directrix x = -3.

• $\left(y-2\right)^2=-16\left(x-1\right)$

• $y^2-16x-4y+20=0$

• $x^2-2x+16y-31=0$

• $y^2+16x-4y-12=0$

Tags

CCSS.HSG.GPE.A.2