Alg 2 Review for Final Ch 3 & Ch 2 (day 1)

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Factor x²-11x+24

• (x-3)(x-8)
• (x-2)(x-12)
• (x+3)(x+8)
• (x+2)(x+12)

Solve by factoring

• -4, 2

• -2, 4

• -16

• -4

Solve by factoring. (HINT: Factor GCF 1st)

• x = 3, x = -6

• x = 0, x = 2

• x = 2, x = 3

• x = -2, x = 1

What are the zeros?

• x= 0 and x= -4
• x= 0 and x= 4
• y= 0
• x= 2

9k² = 225

• 4
• 4, -4
• 25, -25
• -5, 5

Find the zeros of the quadratic equation y=4(x+9)²-36

• x=-9+√6 & x=-9-√6
• x=3 & x=-3
• x=-6 & x=-12
• so solution

• Suzanne made no errors.
  

• Step 2
  

• Step 3
  

• Step 4
  

• Step 5
  

What is the color of the graph that has no real zeros?

• black

• green

• purple

• red

• None of these graphs have no real zeros

What are the solutions to the system:
y = x² + 3x - 5
y = x + 3

• (-4, 2) and (-1, 5)
• (-4, -1) and (2, 5)
• (2, -1 and (-4, 5)
• (-4, 1) and (2, -1)