Final Semester - Kalkulus 1

 $Jika\ f\left(x\right)=2x+1\ maka\ f-invers\left(2\right)\ adalah\ ...$  

• 1/2

• 1

• 2

• 3

• 4

• x-2/-2

• 1/2-x

• 1/2x +1

• x + 1

• x + 2

 $Jika\ diketahui\ f\left(x\right)=x-3\ dan\ g\left(x\right)=2x+4\ ,\ maka\ \left(gof\right)^{-1}\left(2\right)\ adalah...$  

• -4

• -2

• 2

• 4

• 7

 $Diketahui\ f\left(x\right)=\frac{4x+1}{x-4}\ne4.\ invers\ dari\ f\left(x\right)\ adalah\ ...$  

•  $\frac{x+4}{4x-1};\ x\ne-\frac{1}{4}$  

•  $\frac{x-4}{4x+1};\ x\ne-\frac{1}{4}$  

•  $\frac{4x-1}{x+4};\ x\ne-4$  

•  $\frac{4x+1}{x-4};\ x\ne4$  

 $Jika\ f\left(x\right)=\frac{4x-7}{3-x};\ x\ne3\ ,\ maka\ nilai\ invers\ f\left(x\right)\ adalah\ ...$  

•  $\frac{3x-7}{x-4};\ x\ne4$  

•  $\frac{3x-7}{x+4};\ x\ne-4$  

•  $\frac{3x+3}{x-4};\ x\ne4$  

•  $\frac{3x+7}{x+4};\ x\ne-4$  

• HP = {30, 150}

• HP = {30, 390}

• HP = {30, 480}

• HP = {120, 360}

 $Himpunan\ penyelesaian\ persamaan\ \sin2x=-\frac{1}{2},\ \dim ana\ 0^o\le x\le360^o\ adalah\ ...$  

• HP = {95,135,245,335}

• HP = {105, 165, 205, 315}

• HP = {95, 165, 285, 355}

• HP = {105, 165, 285, 345}

 $Himpunan\ penyelesaian\ persamaan\ \cos3x=\frac{1}{2}\sqrt{3},\ untuk\ 0^o\le x\le360^o\ adalah$  

• HP = {10, 110, 130, 260, 280, 350}

• HP = {10,110, 130, 230, 250, 350}

• HP = {110, 130, 230, 280, 310, 350}

• HP = {110, 230, 260, 290, 310, 350}

 $Himpunan\ penyelesaian\ dari\ persamaan\ \cos\left(2x+60^o\right)=-\frac{1}{2},\ untuk\ 0^o\le x\le360^o\ adalah\ ...$  

• HP = {30, 90, 210, 300}

• HP = {30, 90, 120, 210}

• HP = {30, 90, 210, 270}

• HP = {90, 120, 210, 330}

 $Himpunan\ penyelesaian\ dari\ persamaan\ \tan\left(2x-30^o\right)=-\sqrt{3},\ untuk\ 0^o\le x\le360^o\ adalah\ ...$  

• HP = {75, 165, 255, 345}

• HP = {105, 185, 255, 315}

• HP = {75, 105, 165, 205}

• HP = {75, 165, 225, 315}