Fractions | Chapter Assessment | English | Grade 6

Which of the following options is correct with respect to the given fractions?

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Answer explanation

Option 2 is correct. In proper fraction, numerator is less than the denominator. In Improper fraction, numerator is greater than the denominator. Mixed fraction is a combination of whole number and proper fraction.

Which of the following shows the below fractions in ascending order? 12/13, 9/13, 7/13, 15/13, 4/13

• 4/13 < 7/13 < 12/13 < 9/13 < 15/13

• 15/13 < 12/13 < 9/13 < 7/13 < 4/13

• 4/13 < 7/13 < 9/13 < 12/13 < 15/13

• None of the above

Answer explanation

The ascending order of given fractions are 4/13 < 7/13 < 9/13 < 12/13 < 15/13. Hence option 3 is correct.

Tags

CCSS.3.NF.A.3D

Write the shaded portion as fraction for each figure. Arrange them in ascending or descending order using correct sign '<', '=', '>' between the fractions. Click on 'Yes' when it is completed.

• Yes

• No

Answer explanation

The fractions are 4/9, 3/9, 6/9, 4/9 So ascending order is 3/9 < 4/9 = 4/9 < 6/9.

Tags

CCSS.4.NF.A.2

What fraction of a straight angle is a right angle?

• 1/4

• 1/3

• 1/2

• None of the above

Answer explanation

Right angle = 90° Straight angle = 180° Right angle/Straight angle = 90°/180° = 1/2 So, option 3 is correct.

Tags

CCSS.4.MD.C.5B

CCSS.HSG.CO.A.1

Reena painted 21/35 part of a wall and Meena painted 15/25 part of the same wall. Is the part of the wall painted by both of them equivalent?

• Yes

• No

• Cannot be determined.

• Data inadequate

Answer explanation

Reena painted 21/35 part of wall means 21/35 = 3/5 Meena painted 15/25 part of wall means 15/25 = 3/5 The part of wall painted by both of them is equivalent.

Tags

CCSS.3.NF.A.3A

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Pooja had 7/13 litre of milk out which she used 4/11 litre to make kheer. How much milk is left with Pooja?

• 129/143

• 32/143

• 11/143

• 25/143

Answer explanation

Option 4 is correct as 7/13 - 4/11 = (7 × 11)/(13 × 11) - (4 × 13)/(13 × 11) = 77/143 - 52/143 = 25/143

Tags

CCSS.7.NS.A.1C

Mahesh rode his bicycle for 3¾ km in the morning and 9½ km in the evening. The distance travelled by him altogether on that day is _________.

• 5¾ km

• 8¼ km

• 13¼ km

• Cannot be determined

Answer explanation

Distance travelled in the morning = 3¾ km = (3 x 4 + 3)/4 = (12 + 3)/4 = 15/4 km Distance travelled in the evening = 9½ km = (9 x 2 + 1)/2 = (18 + 1)/2 = 19/2 km Total distance travelled = Distance travelled in the morning + Distance travelled in the evening = (15/4 + 19/2) km LCM of denominators of 15/4 and 19/2 is 4. so, 15/4 + 19/2 = 15/4 + (19 x 2)/(2 x 2) = 15/4 + 38/4 = (15 + 38)/4 = 53/4 53/4 = (13 x 4 + 1)/4 = 13¼ Hence, Total distance travelled = 13¼ km So, option 3 is correct.

Tags

CCSS.7.NS.A.1C

Amita did 5/12 part of a project, then Bhavya helped her and completed 7/18 part of the same project. How much part of work is still left to be done?

• 29/36

• 71/36

• 7/12

• 13/18

Answer explanation

Part of project work done by Amita = 5/12 Part of project work done by Bhavya = 7/18 Total work done = 5/12 + 7/18 = 15/36 + 14/36 = 29/36 Work left to be done = 1 - 29/36 = 7/36 Hence option 2 is correct answer.

Tags

CCSS.7.NS.A.1C