Similar Triangles and the Basic Proportionality Theorem (BPT) | Triangles | Assessment | English | Grade 10

Similar Triangles and the Basic Proportionality Theorem (BPT) | Triangles | Assessment | English | Grade 10

10th Grade

4 Qs

quiz-placeholder

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Similar Triangles and the Basic Proportionality Theorem (BPT) | Triangles | Assessment | English | Grade 10

Similar Triangles and the Basic Proportionality Theorem (BPT) | Triangles | Assessment | English | Grade 10

Assessment

Quiz

Mathematics

10th Grade

Hard

CCSS
HSG.SRT.B.4, HSG.SRT.A.2

Standards-aligned

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4 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

It is given that ∆PQR ~ ∆XYZ. Which of the following statements is true? A) PQ / YZ = PR / XY B) PQ / XY = PR / XZ

A

B

Both

Neither

Answer explanation

In the two similar triangles corresponding sides are PQ and XY, QR and YZ, PR and XZ. So, PQ / XY = PR / XZ is the correct statement. Hence, the correct option is Option 2.

Tags

CCSS.HSG.SRT.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In ∆ ABC, points D and E lie on sides AB and AC. It is given that DE ‖ BC, and AD / DB = 3 / 5. If AC = 4.8 cm, find AE.

AE = 1.8 cm

AE = 2.85 cm

AE = 7.2 cm

Answer explanation

Media Image

In ∆ ABC , DE ‖ BC, and AD / DB = 3 / 5 So as per Basic Proportionality Theorem , AD / DB = AE / EC …. ..(1) Now, AC = 4.8 cm and AC = AE + EC Let AE = x , then EC = 4.8 ─ x Putting values in Eq. 1, 3 / 5 = x / (4.8 ─ x) Cross multiplying, 3 ( 4.8 ─ x) = 5x 14.4 ─ 3 x = 5x ..... (2) 8x = 14.4 x = 1.8 cm AE = 1.8 cm So, the correct option is Option 1

Tags

CCSS.HSG.SRT.B.4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A and B are the points on sides PQ and PR respectively of ∆ PQR. PQ =20 cm, PA = 5cm, BR = 6 cm and PB = 2 cm. Is AB ‖ QR ?

Yes

No

Cannot be determined

Answer explanation

Media Image

In ∆ PQR , PQ =20 cm, PA = 5cm, BR = 6 cm and PB = 2 cm . So as per the converse of Basic Proportionality Theorem , AB ‖ QR if PA / AQ = PB / BR …. ..(1) Now, PQ = 20 cm and PQ = PA + AQ So AQ= 20 ─ 5 = 15 Putting values in Eq. 1, PA / AQ = 5 / 15 =1 / 3 PB / BR = 2 / 6 = 1 / 3 Hence , PA / AQ = PB / BR And so, AB ‖ QR So the correct option is Option 1

Tags

CCSS.HSG.SRT.B.4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A girl of height 90 cm is standing at the base of a shed 3.6 m high. If the length of her shadow at a certain time is 2.4 m, find the length of the shadow of the shed at the same time.

12m

9.6m

7.2m

None of the above

Answer explanation

Media Image

Height of girl = BD= 90cm = 0.9 m Height of shed = AB = 3.6 m AD = 3.6 ─ 0.9 = 2.7m Length of shadow of girl=BE = 2.4m EC = x Let length of shadow of shed= BC = 2.4 + x By Basic Proportionality theorem, BD/AD = BE/EC 0.9/2.7 = 2.4/EC EC = (2.7 x 2.4)/0.9 = 7.2m So length of shadow of shed= BC = 2.4 + x = 7.2 + 2.4 = 9.6m So the correct answer is Option 2

Tags

CCSS.HSG.SRT.B.4