Probability: Cases of Dice | Probability | Assessment | English | Grade 10

State True or False. If an unbiased die is thrown, the probability of getting an even number is 1/3.

• TRUE

• FALSE

Answer explanation

If a die is thrown , the total number of Outcomes are --- S = { 1,2,3,4,5,6) Total no. of outcomes (n(S)) = 6 Event A --- Getting an even number A = { 2,4,6} Number of favourable outcomes = 3 n(A)= 3 So, P(A) = 3/6 = 1/2 Hence the given statement is False. Hence the correct answer is option 2.

Tags

CCSS.7.SP.C.7A

Complete the following statement . The Number of possible outcomes when two dice are thrown simultaneously are _______

• 36

• 6

• 12

• 18

Answer explanation

If two dice are thrown simultaneously, the possible outcomes are , S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} n(S) = 36 So the number of possible outcomes are 36 Hence the correct answer is option 1.

A die is thrown once. What is the probability of getting a number >7 ?

• 1/3

• 1/2

• 1/6

• 0

Answer explanation

If a die is thrown , the total number of outcomes are --- S = { 1,2,3,4,5,6) Total no. of outcomes (n(S)) = 6 Event A --- Getting a number > 7 Number of favourable outcomes = 0 This is an impossible event. n(A)= 0 So, P(A) = 0/6 = 0 Hence the correct answer is option 4.

Tags

CCSS.7.SP.C.5

Savita is playing Ludo with her sister Kokila. If Savita gets a 3 on the throw of the die she will be able to cut Kokila's counter on the board and win the game. What is the probability that Savita will lose the game?

• 1 / 6

• 2 / 6

• 5/6

• 3/5

Answer explanation

If a die is thrown , the total number of Outcomes are --- S = { 1,2,3,4,5,6) Total no. of outcomes (n(S)) = 6 Event A --- Getting number 3 A = {3} Number of favourable outcomes = 1 n(A)= 1 So, P(A) = 1/6 So to win the probability is 1/6 To lose probability will be 1 ─ 1/6 = 5/6 So the correct option is Option 3.

Deepak and Niraj throw a pair of dice. If Deepak throws a total of 9, find Niraj's chances of throwing a higher number.

• 16.66%

• 33.33%

• 50 %

• 30%

Answer explanation

If two dice are thrown simultaneously, the possible outcomes are , S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} n(S) = 36 So the number of possible outcomes are 36 n(S) = 36 Event A -- getting a total number greater than 9 A= { (4, 6), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6)} n(A) = 6 Number of Favourable outcomes = 6 P(A) = 6 / 36 = 1/6 So, Niraj's chances of getting more than Deepak = 1/6 = 0.1666 or 16.66% Hence, the correct answer is Option 1.

Tags

CCSS.HSS.CP.B.6