Search Header Logo
  1. Resource Library
  2. Math
  3. Probability And Statistics
  4. Frequency Distribution
  5. Grouped Frequency Distribution | Statistics | Assessment | English | Grade 9

Grouped Frequency Distribution | Statistics | Assessment | English | Grade 9

Authored by Tic Tac Learn

Mathematics

9th Grade

CCSS covered

Grouped Frequency Distribution | Statistics | Assessment | English | Grade 9
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The class mark of the class 250 - 280 is ______

255

260

265

270

Answer explanation

Class mark = (Lower limit + Upper limit)/2 = (250 + 280)/2 = 265

Tags

CCSS.7.SP.B.4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The marks obtained by 10 students in a Mathematics test(out of 100) are given below. 48, 52, 62, 68, 72, 75, 100, 92, 38, 84 Determine the range of the marks.

62

68

60

72

Answer explanation

Range = Highest marks - Lowest marks = 100 - 38 = 62

Tags

CCSS.6.SP.B.5

CCSS.6.SP.A.3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a frequency distribution, the mid - value of a class is 25 and the width of the class is 20. The lower limit of the class is _____

25

15

10

20

Answer explanation

Mid - value = 25 Width = 20 Lower limit = Mid value of class - (Width/2) = 25 - (20/2) = 25 - 10 = 15

Tags

CCSS.6.SP.A.2

CCSS.6.EE.B.7

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The class mark of a class is 45 and if the upper limit of that class is 60, then its lower limit is ______

25

40

50

30

Answer explanation

Upper limit = 60 Class mark = 45 Lower limit = x Now, Class mark = (Lower limit + Upper limit)/2 45 = (x + 60)/2 90 = x + 60 x = 90 - 60 x = 30

Tags

CCSS.6.EE.B.7

CCSS.6.EE.B.5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The mid - value of a class interval is 52. If the class size is 10, find the upper and lower limits of the class.

48 - 58

45 - 55

47 - 57

50 - 60

Answer explanation

Let upper limit and lower limit be x and y, (x + y) /2 = 52 ∴ x + y = 104 ......(1) Now, according to the question x - y = 10 ........(2) Adding equation (1) and (2) we get, 2x = 114 ∴ x = 57 and 57 + y = 104 y = 104 - 57 y = 47 ∴ Required Class Interval is 47 - 57.

Tags

CCSS.7.NS.A.3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Choose the correct frequency distribution table for the data on height (cm) of 20 girls using the class intervals 130 - 135, 135 - 140 and so on. The heights of the girls in cm are: 139, 138, 144, 147, 165, 142, 149, 155, 149, 141, 134, 136, 131, 146, 160, 153, 133, 148, 140, 138

Media Image
Media Image
Media Image
Media Image

Answer explanation

Media Image

Tags

CCSS.6.SP.A.2

CCSS.6.SP.B.5

CCSS.6.SP.A.1

CCSS.6.SP.B.4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The frequency distribution of weights (in kg) of 50 persons is given. What are the class marks of all the class interval?

30, 40, 50, 60, 70

35, 45, 55, 65, 75

30.5, 40.5, 50.5, 60.5, 70.5

35.5, 45.5, 55.5, 65.5, 75.5

Answer explanation

Class mark = (Lower limit + Upper limit)/2 1) (30 + 40)/2 = 35 2) (40 + 50)/2 = 45 3) (50 + 60)/2 = 55 4) (60 + 70)/2 = 65 5) (70 + 80)/2 = 75

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?