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DIVISION of POLYNOMIALS f(x) by Linear Binomials (x+a).

Authored by Godlove Fomukong

Mathematics

10th - 12th Grade

CCSS covered

Used 7+ times

DIVISION of POLYNOMIALS f(x) by Linear Binomials (x+a).
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5 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Given that   x3+2x25x6x3=f(x)+24x3\frac{x^3+2x^2-5x-6}{x-3}=f\left(x\right)+\frac{24}{x-3}  Determine the quotient function,  f(x).f\left(x\right).  

 x2+6x+10.x^2+6x+10.  

 x2+5x+10.x^2+5x+10.  

 x2+12x+10.x^2+12x+10.  

 x3+5x+10.x^3+5x+10.  

Tags

CCSS.HSA.APR.D.6

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Given the identity  \frac{4x^3-3x^2+x+7}{x-2}=4x^2+5x+11\ +\frac{Q}{x-2}.  Determine the numerical value of Q.

30

33

29

-29

Tags

CCSS.HSA.APR.D.6

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Consider the identity function 
  4x33x2+x+7=(x2)(4x2+5x+11)+R.4x^3-3x^2+x+7=\left(x-2\right)\left(4x^2+5x+11\right)+R. Determine the numerical value of the constant  R.R.  

 R=26.R=26.  

 R=27.R=27.  

 R=29.R=29.  

 R=28.R=28.  

Tags

CCSS.HSA.APR.B.2

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 If given a rational function such as  \frac{x^4-26x^2+25}{x-5}\ OR\ \left(x^4-26x^2+24\right)\div\left(x-5\right)  
According to the Remainder Theorem, instead of carrying out long division or synthetic division in order to obtain the remainder,  R,R,   simply plug in the zero obtained simply\ plug\ in\ the\ zero\ obtained\  

 from\ the\ linear\ binomial\ divisor,\ x-5.
 


 for x in the Dividend Function x426x2+25.for\ x\ in\ the\ Dividend\ Function\ x^4-26x^2+25.  Determine the Remainder of the above rational function using the Remainder Theorem.

 1010  

 12-12  

 88  

 00  

Tags

CCSS.HSA.APR.B.2

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

According to the Factor Theorem, any linear  divisor such as (xa)divisor\ such\ as\ \left(x-a\right)  will be a factor of the polynomial  f(x)f\left(x\right)  if and only if   f(a)=0.f\left(a\right)=0.  Using the Factor Theorem, which of the following polynomials has  x5,x-5,  as one of its linear factors?

 x3+2x25x6x^3+2x^2-5x-6  

 x3+2x25x20x^3+2x^2-5x-20  

 x426x2+25x^4-26x^2+25  

 2x53x4+x32x2+x8.2x^5-3x^4+x^3-2x^2+x-8.  

Tags

CCSS.HSA.APR.B.2

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