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DBA - Round 2

Authored by Julio Thomaz

Professional Development

1st - 10th Grade

Used 3+ times

DBA - Round 2
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7 questions

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1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Qual seria a MELHOR forma de otimizar a query abaixo:

SELECT

(SELECT TOP 1 LATITU FROM RODVRA WHERE VEI.CODVEI = RODVRA.CODVEI ORDER BY DATHOR DESC) LATITU,

(SELECT TOP 1 LONGIT FROM RODVRA WHERE VEI.CODVEI = RODVRA.CODVEI ORDER BY DATHOR DESC) LONGIT,

(SELECT TOP 1 DATHOR FROM RODVRA WHERE VEI.CODVEI = RODVRA.CODVEI ORDER BY DATHOR DESC) DATHOR,

VEI.*

FROM RODVEI VEI

WHERE EXISTS (SELECT 1 FROM RODVRA WHERE VEI.CODVEI = RODVRA.CODVEI)

Aplicando INNER JOIN

Aplicando CROSS APPLY

Aplicando OUTER APPLY

Removendo o EXISTS do WHERE

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Collate baseado em Unicode sorting rules são interpretadas mais rápidas que as Non-Unicode sorting rules?

Verdadeiro

Falso

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Na onde é armazenado o Eager Spool?

Master

Tempdb

db_visual_rodopar

MSDB

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Qual função evita o Halloween Problem?

SET

WITH CTE

WITH SCHEMABINDING

WITH(INDEX=IX_TABLE_INDEX)

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Qual função é melhor interpretada após citada diversas vezes pelo SQL?

SET

SELECT

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Caso queira utilizar Function no select, qual teria o melhor resultado?

Campo = FUNCTION(1)

FUNCTION(Campo) = 1

FUNCTION(Campo) = FUNCTION (1)

Nenhuma das anteriores

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Baseado na tabela abaixo, qual comando teria melhor desempenho?

CREATE TABLE FUNCIONARIO(

ID INT IDENTITY(1,1),

NOME VARCHAR(100),

SOBRENOME VARCHAR(100),

ENDERECO VARCHAR(100)

)

DECLARE @NOME Varchar(100); SET @NOME = 'Teste'; SELECT * FROM FUNCIONARIO WHERE NOME = @NOME

DECLARE @NOME Nvarchar(100); SET @NOME = 'Teste'; SELECT * FROM FUNCIONARIO WHERE NOME = @NOME

DECLARE @NOME Text; SET @NOME = 'Teste'; SELECT * FROM FUNCIONARIO WHERE NOME = @NOME

DECLARE @NOME Char(100); SET @NOME = 'Teste'; SELECT * FROM FUNCIONARIO WHERE NOME = @NOME

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