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Mathematics

9th - 12th Grade

CCSS covered

Used 10+ times

Geometry: Volume and Surface Area
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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Find the Surface Area of a cone with a slant height of 7 and a radius of 2. Leave your answer in terms of π.

283π\frac{28}{3}\pi  

56π56\pi  

14π14\pi  

18π18\pi  

2.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

What is the volume of a cube with a surface area of  600 in2600\ in^2  ?

100 in3100\ in^3  

216 in3216\ in^3  

750 in3750\ in^3  

1000 in31000\ in^3  

Tags

CCSS.5.MD.C.5B

CCSS.6.G.A.2

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the volume of a rectangular prism with the given side lengths.

w=4 ft; l=7 ft; h=3.5 ftw=4\ ft;\ l=7\ ft;\ h=3.5\ ft  

98 ft398\ ft^3  

196 ft3196\ ft^3  

58 ft358\ ft^3  

14.5 ft314.5\ ft^3  

Tags

CCSS.7.G.B.6

4.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

A square pyramid has a height of 9 cm and a volume of 75 cm3cm^3  . What is the length of a side of the base?

813 cm8\frac{1}{3}\ cm  

5 cm5\ cm  

25 cm25\ cm  

9 cm9\ cm  

Tags

CCSS.HSG.GMD.A.3

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kuro has a stack of 15 coins on a table with a volume of 8 cubic centimeters. He has stacked them perfectly straight creating a cylindrical shape.

He accidentally bumps the table, causing the coins to shift to a leaning position; but are still stacked. What would be the best estimate of the volume of the stack once it has been bumped/shifted?

9 cubic centimeters

The volume cannot be calculated.

8 cubic centimeters

7 cubic centimeters

Tags

CCSS.3.MD.A.2

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the surface area of a sphere with a radius of 60 centimeters. Leave your answer in terms of π.

288,000π cm2288,000\pi\ cm^2  

240π2240\pi^2  

3600π23600\pi^2  

14,400π214,400\pi^2  

Tags

CCSS.HSG.GMD.A.3

CCSS.8.G.C.9

7.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

The volume of a cone is described by the equation of  V=13πr2hV=\frac{1}{3}\pi r^2h  .

Solve the equation for h.

3πr2V=h\frac{3\pi r^2}{V}=h  

3Vπr=h\sqrt[]{\frac{3V\pi}{r}}=h  

3Vπr2=h\frac{3V}{\pi r^2}=h  

V3πr2=h\frac{V}{3\pi r^2}=h  

Tags

CCSS.HSA.CED.A.4

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