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VECTORS 1R BAT

Authored by AIDA CINCA

Mathematics

12th Grade

Used 12+ times

VECTORS 1R BAT
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10 questions

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1.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Calcula el mòdul o longitud del vector que passa pels punts A=(-1,3) i B=(3,5).

4 54\ \sqrt[]{5}  

5\sqrt[]{5}  

4 24\ \sqrt[]{2}  

2 52\ \sqrt[]{5}  

2.

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

El vector PQ→\overrightarrow{PQ}  =(4, 2) té l'origen en el punt P (3, −1). Determina les coordenades de l'extrem Q.

(a)  

3.

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

Determineu m per tal que el vector (2,m) sigui perpendicular al (3,3)

(a)  

4.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Trobeu l'angle que formen els vectors (2,3) i (-3,4).

82º

46º

71º

19º

5.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Donats els punts A=(-5,6), B=(8,-7), C=(7,-5) calcula AB→ i CB→\overrightarrow{AB}\ i\ \overrightarrow{CB}  

AB→=(3,−1)\overrightarrow{AB}=\left(3,-1\right)  

CB→=(−1,−2)\overrightarrow{CB}=\left(-1,-2\right)  

AB→=(13,−13)\overrightarrow{AB}=\left(13,-13\right)  

CB→=(1,−2)\overrightarrow{CB}=\left(1,-2\right)

AB→=(13,−1)\overrightarrow{AB}=\left(13,-1\right)  

CB→=(−1,2)\overrightarrow{CB}=\left(-1,2\right)

AB→=(−13,13)\overrightarrow{AB}=\left(-13,13\right)  

CB→=(1,−12)\overrightarrow{CB}=\left(1,-12\right)

6.

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

Donats els vectors u→=(4,−4)\overrightarrow{u}=(4,-4)  , v→=(5,−5)\overrightarrow{v}=(5,-5)  , w→=(0,−8)\overrightarrow{w}=(0,-8)   calcula 2u→−3v→+w→2\overrightarrow{u}-3\overrightarrow{v}+\overrightarrow{w}  

Escriu la resposta entre parèntesis i sense separacions: (x,y)

(a)  

7.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Donats els vectors u→=(4,−4)\overrightarrow{u}=(4,-4)  , v→=(2,−5)\overrightarrow{v}=(2,-5)  , w→=(0,−6)\overrightarrow{w}=(0,-6)   expressa el vector w→\overrightarrow{w}   com a combinació linial dels altres dos.

w→=−2u→−4v→\overrightarrow{w}=-2\overrightarrow{u}-4\overrightarrow{v}  

w→=u→+2v→\overrightarrow{w}=\overrightarrow{u}+2\overrightarrow{v}  

w→=−2u→+52v→\overrightarrow{w}=-2\overrightarrow{u}+\frac{5}{2}\overrightarrow{v}  

w→=−u→+2v→\overrightarrow{w}=-\overrightarrow{u}+2\overrightarrow{v}  

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