Lesson 16 quiz

Solve the system by substitution.
 
5x + 4y= −14
y =  −7x  −  15 

• (-2, -1)
• (1, -2)
• (-2, 1)
• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

x + 2y = 2
x = -4y + 2

• (-3, 0)
• (0, 2)
• (-3, -2)
• (2, 0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -6x + 5
-2x + y = 5

• (-3, -6)
• (-6, 3)
• (0, 5)
• (-3, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve each system of equations.
y = 3x - 11  
2x + 3y = 0

• (-2,3)
• (-3,2)
• (3,-2)
• (2,-3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve:
x = -3y - 17
2x + 3y = -7

• (1, -20)
• (3, 0)
• (-5, -2)
• (10 , -9)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

The first step in solving using the substitution method is __________.

• get x by itself
• get y by itself
• get either variable by itself
• add the equations together

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system using the substitution strategy.
 -7x - 2y = -13
X = 2y + 11

• (5,6)
• (3,-4)
• (-4, 4)
• (-3, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

How many solutions?

• One Solution
• No solution
• Infinitely Many Solutions

Tags

CCSS.8.EE.C.8A

Solve:
y = -1x - 5
4x - 8y = 4

• (-3, -2)
• (5, -7)
• (3, 9)
• (-5, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6