Trig Identities Practice

Solve the following for cos²θ:
sin²θ + cos²θ = 1

• cos²θ = 1 - sin²θ
• cosθ = 1 + sin²θ
• cosθ = 1 - sinθ
• cos²θ = Adj/hyp

Tags

CCSS.HSF.TF.C.8

Solve the following for tan²θ:
1 + tan²θ = sec²θ 

• tan²θ = sec²θ + 1
• tan²θ = sec²θ - 1
• tanθ = secθ - 1
• tan²θ = opp/adj

Tags

CCSS.HSF.TF.C.8

CCSS.HSA.REI.A.1

What is csc(x) equivalent to?

• 1/sin(x)
• 1/tan(x)
• sin(x)
• 1/cos(x)

Tags

CCSS.HSF.TF.A.4

Please select the correct solution

• csc x
• sec x
• cot x
• tan x

Tags

CCSS.HSF.TF.C.8

CCSS.HSF.TF.A.2

CCSS.HSF.TF.A.3

CCSS.HSG.SRT.C.6

Tags

CCSS.HSF.TF.A.2

Tags

CCSS.HSF.TF.C.8

• -1

• sin θ

• csc θ

• 1

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

• csc²θ

• sec²θ

• cscθ

• 1

Tags

CCSS.HSF.TF.C.8

• 1/cos x

• 1

• cot x

• -1

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

• 2secθ

• cot²θ

• tan²θ

• sec²θ + 1

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3