
gay-lussac's law
Authored by Galen Reid
Chemistry
9th - 12th Grade
NGSS covered
Used 6+ times

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10 questions
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1.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
The temperature scale used in gas laws is
Celsius
Kelvin
Fahrenheit
2.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Given a constant volume and amount of gas, the formula for gay-lussac's law is
P1/V1 = P2/V2
P1/T1 = P2/T2
P2T1 = P1/T1
3.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Given a constant volume and amount of gas, pressure and temperature are
directionally proportional
inversely proportional
unrelated
kissing cousins
4.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
20 degrees Celsius is _______Kelvin
20
0
273
293
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
To convert from Celsius to Kelvin the formula is
K = C
K = Celsius + 273
K = 273 - Celsius
6.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
The pressure inside a container at 20.0 °C was at 3.00 atm. What is the pressure of the container after its temperature is increased to 50.0 °C? ( P1/T1 = P2/T2) (Convert temperature to Kelvin)
3.3
5
1.8
15.25
7.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20.0 °C to 30.0 °C. Be sure to convert temperature to Kelvin
1.03
1.5
10
2
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