Lesson 8-4|Solving Quadratics by Factoring II

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

Solve:

k² - 2k - 24 = 0

• k = -4, 6

• k = -4, -6

• k = -6, 1

• k = 4, -6

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6
• x = 3 and x = -6
• x = -9 and x = 2
• x = 9 and x = -2

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5
• x = 20 and x = -9
• x = 4 and x = 5
• x = -4 and x = 5

Tags

CCSS.HSA-REI.B.4B

• No Solutions

Tags

CCSS.HSA-REI.B.4B

Solve
 2x² - 3x - 2 = 0

• x = 1, x = -1
• x = -1/2, x = 2
• x = 1/2, x = 2
• x = 1/2, x = 1

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.HSA-REI.B.4B