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(04/21 & 04/22) 7th Pd Unit 5B Quiz: Exponential Word Problems

Authored by Beatrice Thames

Mathematics

9th - 12th Grade

CCSS covered

Used 5+ times

(04/21 & 04/22) 7th Pd Unit 5B Quiz: Exponential Word Problems
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6 questions

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1.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Media Image

The value of a car purchased for $20,000 decreases at a rate of 12% per year. What will be the value of the car after 3 years?

$12,800.00

$13,629.44

$17,600.00

$28,098.56

Tags

CCSS.HSF.BF.A.2

2.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Suppose a culture of bacteria begins with 5000 cells and dies by 30% each year. Write an equation that represents this situation.

Tags

CCSS.HSF.LE.A.2

3.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

 Calculate the value of each investment then determine which investment would be worth the most after 30 years.?

An initial investment of $7000 is compounded monthly at a rate of 4.5% for 30 years.

An initial investment of $7000 is compounded quarterly at a rate of 4.8% for 30 years.

An initial investment of $7000 is compounded continuously at a rate of 5% for 30 years.

They are all equal

4.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

A culture of bacteria triples by the end of each hour. If there are 568 bacteria in a culture at 5 PM, then how many bacteria were there at 1 PM (i.e 4 hours ago)?

(ROUND TO THE NEAREST WHOLE NUMBER)

46008

9088

35

7

Tags

CCSS.HSF.LE.A.4

5.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Victor bought his truck new for $34,000. Its value decreases 6.5 % each year. In approximately, how many years will the value of the truck be half of what he paid for it?

(HINT: Activating Strategy)

10.3 Years

11. 5 Years

12.8 Years

13.3 Years

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The value of a new car depreciates over time. Alice purchased a new car in May 2017. The value, , of her car after  years can be modeled by the equation  log0.8(V28,000)=t\log_{0.8}\left(\frac{V}{28,000}\right)=t 

If you wanted to know the specific value (v) of the car after years, how could you rewrite the equation|?

 V=log0.8(28,000)V=\log_{0.8}\left(28,000\right) 

 V= 28,000(8)tV=\ 28,000\left(8\right)^t  

 V=28000(0.8)tV=28000\left(0.8\right)^t 

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