Probabilitatea
Quiz
•
Mathematics
•
10th - 11th Grade
•
Practice Problem
•
Hard
Iurgi Arginzoniz
Used 4+ times
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8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Zein da Gabonetako Loterian zure zenbakia ateratzeko probabilitatea?
1/100.000
1/99.999
1/10
1/10.000
Answer explanation
Loteriako zenbakiak 00000tik 99.999ra doaz. Hau da, 100.000 zenbaki ezberdin daude guztira.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Kiniela bat irabazteko 15 partidatako emaitza asmatu behar da (1, x, 2). Zein da 15ak asmatzeko probabilitatea?
Answer explanation
Partida bakoitzan 3 gauza gertatu daitezka, beraz partida bat asmatzeko probabilitatea 1/3 da. Bi asmatzeko, 1/3*1/3... eta horrela 15 partida igarri arte: 1/3^15
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
ZUZENA
OKERRA
BAI
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
6 aurpegiko dado bat jaurti eta ondoren beste bat jaurtizen dugu. Zein da bietan emaitza berdina ateratzeko probabilitatea?
Answer explanation
Lehen tiradan edozein zenbaki aterako da, berdin dio (adibidez 3). Zein da bigarrenean zenbaki berdina berriz ateratzeko aukera? 1/6, Laplacen arauaren arabera.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Bi dado bota eta bietan emaitza ezberdina ateratzeko probabilitatea, zein da?
Answer explanation
Bi dado botatzerakoan 36 aukera ezberdin daude. Horietako 6tan, bi dadoek zenbaki berdina daukate (11,22,33,44,55,66), beraz 6/36=1/6 dira bi berdinak ateratzeko aukerak. Bi ezberdinak ateratzea aurkako gertaera da, beraz: P=1-1/6
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Answer explanation
B gertaera honako hau da: B={4,5,6,9} eta Lagin-espazioa 9 da (1,2,3,4,5,6,7,8,9).
P(B)=4/9
Beraz, Bren aurkakoa hau da: B'={1,2,3,7,8}.
P(B')=1 - P(B) = 1 - 4/9
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Zein da zuzena?
Denak Okerrak
8.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Hau da Bilboko eguraldia arrataslde honetan. Zein da 3 ordu JARRAIAN euria egiteko probabilitatea?
Answer explanation
3 orduetan euria egiteko, lehenengo orduan egin behar du (0,7) eta baita bigarrenean eta hirugarrenean. Hau da 0,7*0,6*0,5; hiru gertaerak eman behar dira eta emaitza, beraz, horien biderketa da.
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