Area of Triangle 1/2absinC

The area of the triangle is

• ½ x 8 x 9 x sin 72^o

• ½ x 9 x 10 x sin 72^o

• ½ x 8 x 10 x sin 72^o

The area of the triangle is

• ½ x 7.6 x 5.89 x sin 66.9^o

• ½ x 7.64 x 5.89 x sin 66.9^o

• ½ x 7.64 x 5.89 x sin 45.5^o

• ½ x 7.64 x 5.89 x sin 66.9^o

To find the area of the triangle...

• Step 1: a = 7 cos 25^o; Step 2: ½ x 7 x (7 cos 25^o) x sin25^o

• Step 1: a = 7 sin 25^o; Step 2: ½ x 7 x (7 sin 25^o) x sin25^o

• Step 1: b = 7 tan 25^o; Step 2: ½ x 7 x (7 tan 25^o) x sin25^o

• Step 1: b = 7 sin 25^o; Step 2: ½ x 7 x (7 sin 25^o) x sin25^o

Which steps below shows the correct way to get the shortest distance from A to BC?

• Step 1: Area = ½ x 8 x 12 x sin 89.6^o; Step 2: Shortest distance = (Area) ÷ (½ x 8)

• Step 1: Area = ½ x 8 x 9 x sin 89.6^o; Step 2: Shortest distance = (Area) ÷ (½ x 9)

• Step 1: Area = ½ x 8 x 9 x sin 89.6^o; Step 2: Shortest distance = (Area) ÷ (½ x 12)

• Shortest distance = 9 cos 44.8^o