KIMIA KELAS 12 - SIFAT KOLIGATIF LARUTAN

Quiz
•
Chemistry, Science
•
12th Grade
•
Hard
Mariska Witanti
Used 242+ times
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
Pernyataan yang tepat mengenai sifat koligatif larutan adalah ...
Sifat koligatif larutan bergantung pada jumlah partikel zat pelarut
Sifat koligatif larutan bergantung pada jenis zat terlarut
Sifat koligatif larutan bergantung pada jumlah partikel zat terlarut
Tekanan uap suatu zat merupakan sifat koligatif larutan yang tergantung pada jenis zat
2.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
Ke dalam 250 gram air dilarutkan 8,7 gram K2SO4 (Mr = 174). Jika Kb air adalah 0,52°C/molal, tentukan kenaikan titik didih larutan tersebut!
0,1250 C
0,3120 C
0,5240 C.
0,2130 C
3.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
Sebanyak 4,5 gram glukosa (Mr =180) dilarutkan ke dalam 90 gram air (Mr=18). Jika te kanan uap jenuh pelarut pada suhu 25o C adalah 240 mmHg, maka tekanan uap larutan adalah ...
4.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
Tentukan tekanan osmosis larutan glukosa (Mr = 180) yang dibuat dengan melarutkan 10,8 gram glukosa dalam air hingga volumenya 400 mL pada suhu 27°C. Gunakan R = 0,082 L atm/mol K.
0,18 atm
4,16 atm
3,69 atm
2,54 atm
5.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
Data titik beku dari percobaan sifat koligatif larutan ditunjukkan oleh gambar termometer berikut!
Diantara jawaban berikut, mana yang sesuai dengan larutan X dan Y?
Larutan X: glukosa 0,5 m
Larutan Y: natrium klorida 0,5 m
Larutan X: urea 0,5 m
Larutan Y: natrium klorida 1 m
Larutan X: natrium klorida 0,5 m
Larutan Y: urea 2 m
Larutan X: urea 1 m
Larutan Y: glukosa 0,5 m
6.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
Berapa tekanan osmosis larutan naftalen dalam benzena yang mengandung 10 gr naftalen (Mr = 128) tiap 1 liter larutan pada suhu 150 C? (R = 0,082 L atm/mol K)
1,84 atm
1,74 atm
0,18 atm
18, 4 atm
7.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
8 gr C12H22O11 dilarutkan dalam 60 gr air. (Mr C12H22O11 =342, Kb air = 0,512 0 C Kg/mol dan Tb air = 100 0 C ). Hitunglah! ∆Tb larutan?
100,40C
0,40C
0,20C
100,20C
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