02 IM Congruence

Triangles ABC and DCB are congruent by the Angle-Angle Triangle Congruence Theorem

Triangles ABC and BCD are congruent by the Angle-Side-Angle Triangle Congruence Theorem.

Triangles ABC and BCD are congruent by the Side-Side-Side Triangle Congruence Theorem.

Triangles ABC and DCB are congruent by the Side-Angle-Side Triangle Congruence Theorem.

Triangles ABC and DCB are congruent by the Side-Side-Side Triangle Congruence Theorem.

Rotate $$\Delta GHJ$$  using center G until GH is lined up with ST and then reflect over a line halfway between $$\Delta G'H'J'$$ and $$\Delta STU$$  .

Translate $$\Delta GHJ$$  by the directed line segment GS. Rotate $$\Delta G'H'J'$$   using S as the center by angle $$\angle H'ST$$  . Reflect $$\Delta G"H"J"$$ over ST.

Translate $$\Delta GHJ$$  by the directed line segment GT. Rotate G'H'J' using T as the center by $$\angle H'TS$$  . Reflect $$\Delta G"H"J"$$  over ST.

Translate $$\Delta GHJ$$   by the directed line segment GS. Translate $$\Delta G'H'J'$$  by the directed line segment H'T. Translate $$\Delta G"H"J"$$  by the directed line segment J"T.

The image of U and J are on the same side of ST and make the same angle with it at T.

The image of U and J are the same distance along the same ray from T.

The image of U and J will not coincide after reflection over ST.

Line ST is the perpendicular bisector of the auxilary segment connecting U and J, because the perpendicular bisector is determined by two points that are both equidistant from the endpoints of a segment.

$$AD\parallel DC$$  

$$m\angle DAB+m\angle ADC=180\degree$$  

$$BC\perp DC$$  

$$segment\ AM\cong segment\ MC$$  

$$\angle AMD\cong\angle CMB$$  

40˚

140˚

70˚

Not enough information.

Alternate interior angles

As marked in diagram.

Angle Addition Postulate.

Triangle Sum Theorem

HL Triangle Congruence

AAS Triangle Congruence

SSS Triangle Congruence

Not enough information

ASA Triangle Congruence