Rearranging Equations (Medium)

Authored by Ben Passmore

Mathematics

9th - 10th Grade

CCSS covered

Used 12+ times

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7 questions

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MATH RESPONSE QUESTION

3 mins • 3 pts

Make $x$ the subject in $a=\frac{2x+6}{5}$ .

$x=\frac{5a-6}{2}$

Mathematical Equivalence

Tags

CCSS.HSA.CED.A.4

MATH RESPONSE QUESTION

3 mins • 3 pts

Make $a$ the subject in the equation $4x=\frac{3\left(2a-3\right)}{2}$

$a=\frac{4}{3}x+\frac{3}{2}$

Mathematical Equivalence

Tags

CCSS.HSA.CED.A.4

MATH RESPONSE QUESTION

3 mins • 3 pts

Make $p$ the subject in the equation $\frac{3p}{4}=\frac{4\left(2x+3\right)}{5}$ .

$p=\frac{16\left(2x+3\right)}{15}$

Mathematical Equivalence

Tags

CCSS.HSA.CED.A.4

MATH RESPONSE QUESTION

2 mins • 2 pts

Make $x$ the subject in the equation $2p+5d=\frac{x+6}{2}$ .

$x=4p+10d-6$

Mathematical Equivalence

Tags

CCSS.HSA.CED.A.4

MATH RESPONSE QUESTION

3 mins • 3 pts

Make $y$ the subject of the equation $x^2=2y^2+\frac{1}{3}$ .

$y=\sqrt[]{\frac{x^2}{2}-\frac{1}{6}}$

Mathematical Equivalence

Tags

CCSS.HSA.CED.A.4

MATH RESPONSE QUESTION

3 mins • 3 pts

Make $a$ the subject of the equation $\left(a+2\right)^2=2\left(b+2\right)$

$a=\sqrt[]{2\left(b+2\right)}-2$

Mathematical Equivalence

Tags

CCSS.HSA.CED.A.4

MATH RESPONSE QUESTION

3 mins • 3 pts

Make $x$ the subject in the equation $\frac{\sqrt[]{x+1}}{2}=2\left(y+1\right)$

$x=\left(4y+4\right)^2-1$

Mathematical Equivalence

Tags

CCSS.HSA.CED.A.4

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Rearranging Equations (Medium)

Make xxx the subject in a=2x+65a=\frac{2x+6}{5}a=52x+6​ .

Make aaa the subject in the equation 4x=3(2a−3)24x=\frac{3\left(2a-3\right)}{2}4x=23(2a−3)​

Make ppp the subject in the equation 3p4=4(2x+3)5\frac{3p}{4}=\frac{4\left(2x+3\right)}{5}43p​=54(2x+3)​ .

Make xxx the subject in the equation 2p+5d=x+622p+5d=\frac{x+6}{2}2p+5d=2x+6​ .

Make yyy the subject of the equation x2=2y2+13x^2=2y^2+\frac{1}{3}x2=2y2+31​ .

Make aaa the subject of the equation (a+2)2=2(b+2)\left(a+2\right)^2=2\left(b+2\right)(a+2)2=2(b+2)

Make xxx the subject in the equation x+12=2(y+1)\frac{\sqrt[]{x+1}}{2}=2\left(y+1\right)2x+1​​=2(y+1)

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Make $x$ the subject in $a=\frac{2x+6}{5}$ .

Make $a$ the subject in the equation $4x=\frac{3\left(2a-3\right)}{2}$

Make $p$ the subject in the equation $\frac{3p}{4}=\frac{4\left(2x+3\right)}{5}$ .

Make $x$ the subject in the equation $2p+5d=\frac{x+6}{2}$ .

Make $y$ the subject of the equation $x^2=2y^2+\frac{1}{3}$ .

Make $a$ the subject of the equation $\left(a+2\right)^2=2\left(b+2\right)$

Make $x$ the subject in the equation $\frac{\sqrt[]{x+1}}{2}=2\left(y+1\right)$