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What should be the minimum diameter of longitudinal bar in a column as per IS 456:2000

• 10

• 12

• 16

• 20

As per IS 456:2000 what should the minimum area of longitudinal reinforcement in column? Consider width of column B, overall depth D, and effective depth d.]

• 0.006 BD

• 0.008 BD

• 0.006 Bd

• 0.008 Bd

As per IS 456:2000 what should be the nominal cover for a column of size 250mmX250mm, having 4 nos. 16mm Fe415 grade of steel.]

• 20 mm

• 30 mm

• 40 mm

• 50 mm

A short column of size 350mmx450mm is subjected to a service axial load of 1000kN. If diameter of longitudinal steel provided is 25 mm, then the minimum diameter of tie that can be provided to the column is

• 12 mm.

• 10mm

• 8mm

• 6mm

What would be the maximum spacing between two ties as per IS 456:2000 for a column of size 250mmx350mm, if diameter of tie is 8mm and diameter of longitudinal bars is 20mm

• 320 mm

• 300 mm

• 250 mm

• 150 mm

An axially loaded column of size 450mmx550mm subjected to a service load of 1800 kN. Length of the column is 3.5m and its both ends are hinged. What is the percentage of steel required to resist the service load? Consider grade of concrete and steel as M20 and Fe415 respectively

• 0.70%

• 2.50 %

• 3.55 %

• 1.08 %

Maximum allowable compressive strain in concrete under axial compression as per IS 456:2000 is

• 0.0035

• 0.0020

• 0.0030

• 0.0045

As per IS 456:2000 in case of column relation between effective length (L) and its least lateral dimension (B) could be

• L<3B

• L>3B

• B>3L

• B<3L

A rectangular column of size 400mm × 450mm is reinforced with 6 nos. 20 mm dia bars equally divided in opposite sides. The grade of concrete is M20 and the grade of steel is Fe415. The computed axial force, Puz required for calculation of Pu/Puz according to limit state method in IS456:2000 is equal to

• 2190kN

• 2737 kN

• 1642 kN

• 3285 kN

A rectangular column of size 400mm × 450mm is reinforced with 6 nos. 20 mm dia bars equally divided in opposite sides. The grade of concrete is M20 and the grade of steel is Fe415. The applied axial force, Pu is equal to 1400kN. Based on Pu/Puz, the value αn according to limit state method in IS456:2000 is equal to

• 2.598

• 2.165

• 1.299

• 1.732