Na figura, o trapézio OTUQ está dividido em 5 triângulos retângulos, isósceles e congruentes. Utilizando as letras da figura, indica um vetor simétrico ao vetor O Q → \overrightarrow{OQ} O Q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> .

S P → \overrightarrow{SP} S P <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

P S → \overrightarrow{PS} P S <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

R Q → \overrightarrow{RQ} R Q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

Q R → \overrightarrow{QR} Q R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

A K → + L B → = − \overrightarrow{AK}+\overrightarrow{LB}=_- A K <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z"> + L B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z"> = − Usando as letras da figura completa:

0 → \overrightarrow{0} 0 <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z">

K B → \overrightarrow{KB} K B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z">

K L → \overrightarrow{KL} K L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z">

A B → \overrightarrow{AB} A B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z">

Vetores

Authored by Cláudia Morgado

Mathematics

8th Grade

Used 4+ times

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MULTIPLE SELECT QUESTION

1 min • 1 pt

A soma de um ponto com um vetor é um:

Ponto.

Vetor.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

MULTIPLE CHOICE QUESTION

1 min • 1 pt

MULTIPLE CHOICE QUESTION

1 min • 1 pt

MULTIPLE CHOICE QUESTION

1 min • 1 pt

MULTIPLE CHOICE QUESTION

1 min • 1 pt

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Na figura, o trapézio OTUQ está dividido em 5 triângulos retângulos, isósceles e congruentes.
Utilizando as letras da figura, indica um vetor simétrico ao vetor
$\overrightarrow{OQ}$ .

$\overrightarrow{SP}$

$\overrightarrow{PS}$

$\overrightarrow{RQ}$

$\overrightarrow{QR}$

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\overrightarrow{AK}+\overrightarrow{LB}=_-$
Usando as letras da figura completa:

$\overrightarrow{KB}$

$\overrightarrow{KL}$

$\overrightarrow{AB}$

$\overrightarrow{0}$

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Vetores

A soma de um ponto com um vetor é um:

Na figura, o trapézio OTUQ está dividido em 5 triângulos retângulos, isósceles e congruentes.Utilizando as letras da figura, indica um vetor simétrico ao vetor OQ→\overrightarrow{OQ}OQ​ .

Dois vetores que têm mesma direção, o mesmo comprimento e sentidos contrários, dizem-se:

AK→+LB→=−\overrightarrow{AK}+\overrightarrow{LB}=_-AK+LB=−​ Usando as letras da figura completa:

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Discover more resources for Mathematics

Na figura, o trapézio OTUQ está dividido em 5 triângulos retângulos, isósceles e congruentes.
Utilizando as letras da figura, indica um vetor simétrico ao vetor
$\overrightarrow{OQ}$ .

$\overrightarrow{AK}+\overrightarrow{LB}=_-$
Usando as letras da figura completa: