Exam Review Quads

Factor
x² + 9x - 36

• (x + 12)(x - 3)
• (x + 9)(x - 4)
• (x - 12)(x + 3)
• (x - 9)(x - 4)

Factor:

5x³ - 7x²

• x²(5x - 7)

• x(5x² - 7x)

• x³(5 - 7x)

• Prime

Factor: 25x² - 9

• (5x + 3)(5x - 3)

• (x + 5)(x - 3)

• (x - 3)(x + 5)

• (5x + 3)(3x + 5)

Factor d² - 10d + 25

• (d + 5) (d - 5)
• (d - 15) (d + 10)
• (d + 5) (d - 20)
• (d - 5) (d - 5)

Factor:  6x² + 9x

• (6x + 1)(x + 3)
• (3x + 1)(2x + 3)
• 3x(2x + 3)
• 6x(x + 3)

Find GCF 15n³+25n²

• 5
• 15n
• 5n²
• 5n

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Solve
x² + 2x - 24 = 0

• x = -6, x = 4
• x = 6, x = -4
• x = 12, x = -2
• x = 8, x = -3

Solve by factoring:  2x²+ 7x + 6 = 0

• x= 3/2 and x = 2
• x = -3/2 and x = -2
• x = 6 and x = 7
• x = -6 and x = -7