quadratic graphs 2

Which of the following equations could represent the parabola shown?

• $y=-\left(x-3\right)^2-1$

• $y=\left(x-3\right)^2-1$

• $y=-\left(x+3\right)^2-1$

• $y=-\left(x-1\right)^2-3$

• $y=-\left(x-3\right)^2+1$

The parabola

 $y=-x^2\$  
is translated 6 units to the left. What is its new equation?

•  $y=-6x^2$  

•  $y=-x^2+6$  

•  $y=-\left(x+6\right)^2$  

•  $y=-\left(x-6\right)^2$  

•  $y=-x^2-6$  

What is the domain of the function?
*Hint: Domain is the set of all x-values included in the function.

• x≥3
• x≤3
• All real numbers
• -1≤x≤5

What is the vertex of the parabola?

Which statement is true?

• A parabola must have two x-intercepts.

• A parabola can have two, one or no x-intercepts.

• Some parabolas do not have a y-intercept.

• Some parabolas do not have a turning point.

• The axis of symmetry is half way between the x-intercept and the y-intercept.

What is the y-intercept of the parabola:

 $y=\left(x-1\right)^2-4$  ?

•  $\left(0,-4\right)$  

•  $\left(0,-3\right)$  

•  $\left(0,\ 1\right)$  

•  $\left(3,0\right)$  

•  $\left(-1,0\right)$  

The parabola  $y=-x^2$  is translated 4 units up. What is its new equation?

•  $y=x^2-4$  

•  $y=-x^2+4$  

•  $y=-\left(x-4\right)^2$  

•  $y=-\left(x+4\right)^2$  

•  $y=-x^2-4$  

Use the picture to find the vertex and axis of symmetry

• Vertex (3,8) Axis x = 3

• Vertex (3,8) Axis y = 3

• Vertex (8,3) Axis x = 3

• Vertex (8,3) Axis y = 3

How many solutions does this graph have?

• one
• two
• no solutions
• cannot be determined

What is the green dashed line called?

• roots or x-intercepts

• parabola

• axis of symmetry

• y intercept