Systems of Equations

Solve the system of equations
y = 5x + 1
y = 3x + 13

• (6, 31)
• (31, 6)
• (4, 21)
• (2, 11)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations.
y = 4x+1
3x + 2y = 13

• (1, 5)
• (5, 1)
• (0.25, 2)
• ∅

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
4x+9y=28
-4x-y=-28

• (-7,0)
• (6,0)
• (-6,0)
• (7,0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system
2x - 3y = -6
-2x - 2y = 26

• (-9,-4)
• (9,4)
• (4,9)
• (-4,-9)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system
x + 9y = 8
-6x - 9y = -3

• (1,-1)
• (1,1)
• (-1,1)
• (-1,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Is this system ready for elimination?

• Yes, the x variables will eliminate.

• Yes, the y variables will eliminate.

• No, you need a multiplier.

• Not enough information.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (-2, 6)

• (6, -2)

• (-2, 0)

• (0, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Say you wanted to eliminate x from the system shown. How would you do it?

• Add the equations without doing any multiplication.

• Multiply the first equation by 2 and the second equation by 3, then add the equations.

• Multiply the first equation by negative 2 and the second equation by 3, then add the equations.

• Multiply the first equation by 3 and the second equation by negative 2, then add the equations.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using the substitution method

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using the substitution method:

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6