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Cubic & Cube Root Homework

Authored by Christian Baxley

Mathematics

9th - 12th Grade

Used 9+ times

Cubic & Cube Root Homework
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21 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Identify the domain of the cubic parent function f(x) = x3f\left(x\right)\ =\ x^3

(0 , ∞)\left(0\ ,\ \infty\right)

(−∞ , ∞)\left(-\infty\ ,\ \infty\right)

[0 , ∞)\left[0\ ,\ \infty\right)

[−∞ , ∞]\left[-\infty\ ,\ \infty\right]

2.

MULTIPLE SELECT QUESTION

5 mins • 1 pt

Media Image

Identify the range of the cubic parent function f(x) = x3f\left(x\right)\ =\ x^3 .

Select two correct answers.

y ≥ 0y\ \ge\ 0

y > 0y\ >\ 0

All Real Numbers

(−∞ , ∞)\left(-\infty\ ,\ \infty\right)

3.

DRAG AND DROP QUESTION

1 min • 1 pt

The domain for the function f(x) = 13(x−2)3+4f\left(x\right)\ =\ \frac{1}{3}\left(x-2\right)^3+4 is ​ (a)   while the range is (−∞,∞)\left(-\infty,\infty\right) .

(−∞,∞)\left(-\infty,\infty\right)  

[2,∞]\left[2,\infty\right]  

[−2,∞]\left[-2,\infty\right]  

[2,∞)\left[2,\infty\right)  

[−2,∞)\left[-2,\infty\right)  

(−2,∞)\left(-2,\infty\right)  

4.

DRAG AND DROP QUESTION

1 min • 1 pt

The domain for the function f(x) = 13(x−2)3+4f\left(x\right)\ =\ \frac{1}{3}\left(x-2\right)^3+4 is ​ (a)   while the range is (−∞,∞)\left(-\infty,\infty\right) .

(−∞,∞)\left(-\infty,\infty\right)  

[2,∞]\left[2,\infty\right]  

[−2,∞]\left[-2,\infty\right]  

[2,∞)\left[2,\infty\right)  

[−2,∞)\left[-2,\infty\right)  

(−2,∞)\left(-2,\infty\right)  

5.

DROPDOWN QUESTION

1 min • 1 pt

The function f(x)=x3f\left(x\right)=x^3 was ​ (a)   by a factor of 1/3, shifted ​ (b)   2 units, and shifted ​ (c)   4 units to create the function g(x) = 13f(x−2)+4g\left(x\right)\ =\ \frac{1}{3}f\left(x-2\right)+4 .

vertically compressed
right
up
vertically stretched
left
down

6.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Identify the equation of the function f(x) = x3f\left(x\right)\ =\ x^3 that has been reflected across the x-axis, and shifted 2 units up.

g(x)=f(−x+2)g\left(x\right)=f\left(-x+2\right)

g(x) = −f(x)+2g\left(x\right)\ =\ -f\left(x\right)+2

g(x) = f(−x)+2g\left(x\right)\ =\ f\left(-x\right)+2

g(x)=−f(x+2)g\left(x\right)=-f\left(x+2\right)

7.

MATH RESPONSE QUESTION

3 mins • 1 pt

33 = 3^3\ =\

2727

Mathematical Equivalence

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