Integration by Substitution Practice

$$\frac{1}{2}(3x⁴+2)⁴+C$$

$$(3x⁴+2)⁴+C$$

$$\frac{1}{5}(3x⁴+2)⁵+C$$

$$\frac{1}{3}(3x⁴+2)⁶+C$$

$$\frac{1}{3}(x^4+3)^3+C$$

$$\frac{1}{12}(x^4+3)^3+C$$

$$\frac{3}{4}(x^4+3)^3+C$$

$$\frac{1}{4}(x^4+3)^3+C$$

$$6x^2+12x+C$$  

$$x^{2\ }-2x+C$$  

$$3x^2+6x+C$$  

$$2x^3+6x^2+C$$

$$\cos\left(2x\right)+C$$  

  $$-\frac{1}{2}\cos\left(2x\right)+C$$  

$$-\cos\left(2x\right)+C$$  

$$\frac{1}{2}\cos\left(2x\right)+C$$  

$$\frac{\left(2x+5\right)^8}{8}+c$$  

$$\frac{\left(x^2+5\right)^8}{16}+c$$  

$$\frac{\left(x^2+5\right)^6}{6}+c$$  

$$\frac{\left(2x+5\right)^8}{16}+c$$  

$$\frac{1}{2\sqrt{3+x^2}}+C$$  

$$\sqrt{3+x^2}+C$$  

$$2\sqrt{3+x^2}+C$$  

$$\frac{2}{\sqrt{3+x^3}}+C$$  

$$2\left(\tan4x\right)^{\frac{3}{2}}+C$$

$$\frac{15}{4}\cdot\left(\tan4x\right)^{\frac{4}{3}}+C$$

$$\frac{4}{3}\cdot\left(\tan4x\right)^{\frac{3}{2}}+C$$

$$\frac{2}{3}\cdot\left(\tan4x\right)^{\frac{3}{2}}+C$$

$$\frac{3}{4}$$

$$-\frac{5}{4}$$

$$\frac{21}{64}$$

$$\frac{65}{192}$$