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Titik Stasioner, Fungsi Naik dan Fungsi Turun

Authored by Santi Pebriany

Mathematics

12th Grade

Used 35+ times

Titik Stasioner, Fungsi Naik dan Fungsi Turun
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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 2 pts

Diketahui fungsi kurva y = x3 − 3x2 − 24 x  y\ =\ x^{3\ }-\ 3x^2\ -\ 24\ x\ \ maka nilai stasionernya adalah ...

-35 dan 1

-1 dam 34

-2 dan 4

21 dan -87

21 dan -77

2.

MULTIPLE CHOICE QUESTION

45 sec • 2 pts

Tentukan titik stasioner dari fungsi berikut f(x) =2x3 − 3x2 −12x + 4f\left(x\right)\ =2x^3\ -\ 3x^2\ -12x\ +\ 4

(2,4) dan (-1,31)

(-2,4) dan (1,31)

(-2,20) dan (1,11)

(2,20) dan (-1,11)

(2,20) dan (1,11)

3.

MULTIPLE CHOICE QUESTION

45 sec • 2 pts

Fungsi f(x) =3x2−6x + 5 f\left(x\right)\ =3x^2-6x\ +\ 5\ naik pada interval

x<1x<1

x>1x>1

x>2x>2

x<12x<12

x>−1x>-1

4.

MULTIPLE CHOICE QUESTION

45 sec • 2 pts

Fungsi f(x) =−4x2 +24x − 10 f\left(x\right)\ =-4x^2\ +24x\ -\ 10\ turun dalam interval...

x<2x<2

x>2x>2

x<3x<3

x>−2x>-2

x>3x>3

5.

MULTIPLE CHOICE QUESTION

45 sec • 2 pts

Fungsi f(x) = x3−9x2+24x−12 f\left(x\right)\ =\ x^3-9x^2+24x-12\ naik dalam interval

x<2 atau x>4x<2\ atau\ x>4

2<x<42<x<4

x<−2 atau x>4x<-2\ atau\ x>4

−2<x<4-2<x<4

−4<x<2-4<x<2

6.

MULTIPLE CHOICE QUESTION

45 sec • 2 pts

Diketahui fungsi f(x)=x2−8x−9f\left(x\right)=x^2-8x-9 naik pada interval...

x > 4

x < 4

x > -4

x < 6

x > 6

7.

MULTIPLE CHOICE QUESTION

1 min • 3 pts

Fungsi f(x) = x4 — 18x2 turun pada interval...

x < 0 atau x > 3

x < 0 atau x > -3

x < -3 atau 0 < x < 3

-3 < x < 0 atau x > 3

x > -3

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