factoring a sum or difference of two cubes

Factor 64-27a³

• (4-3a)(9a²+12a+16)

• (3a-4)(3a²+12a+16)

• (4-3a)(3a²+12a+16)

• (4-3a)³

Complete the formula
a³-b³=

• (a-b)(a²+ab+b²)
• (a+b)(a²-ab+b²)
• (a-b)(a²-ab+b²)
• (a+b)(a²+ab+b²)

The binomial 

 $x^3+y^3$ is called a/an _________.

• Difference of Two Squares

• Sum of Two Cubes

• Difference of Two Cubes

• Square of a Binomial

Factor completely $64x^6+y^6$ 

•  $\left(4x^2+y^2\right)\left(16x^4-4x^2y^2-y^4\right)$  

•  $\left(4x^2-y^2\right)\left(16x^4+4x^2y^2+y^4\right)$  

•  $\left(4x^2+y^2\right)\left(16x^4-4x^2y^2+y^4\right)$  

•  $\left(4x^2-y^2\right)\left(16x^4-4x^2y^2-y^4\right)$  

Which of the following is the complete factored form of $x^3y^9+1000$  

•  $\left(xy^3+10\right)\left(x^2y^6-10xy^3+100\right)$  

•  $\left(xy^{ }+10\right)\left(x^2y^2-10xy^{ }+100\right)$  

•  $\left(xy^3-10\right)\left(x^2y^6+10xy^3+100\right)$  

•  $\left(xy^3-10\right)\left(x^2y^6-20xy^3+100\right)$  

What must be multiplied to $\left(5x^2+2y\right)$  to get a product of  $125x^6+8y^3$  ?

•  $\left(5x^2+2y\right)$  

•  $\left(5x^2-2y\right)$  

•  $\left(5x^4+10x^2y+2y^2\right)$  

•  $\left(25x^4-10x^2y+4y^2\right)$  

Factor the following binomial: 8x³-27

• (2x+3)(4x²-6x+9)

• (2x-3)(4x²+6x+9)

• (2x-3)(4x²+6x-9)

• (2x-3)(2x²+6x+9)

Fully Factor the Following
8x³-27

• (2x+3)(4x²-6x+9)
• (2x-3)(4x²+6x+9)
• (2x-3)(4x²+6x-9)
• (2x-3)(2x²+6x+9)

WHAT FACTORING TECHNIQUE YOU HAVE TO USE TO SOLVE FOR THE FACTORS OF 27X³-343?

• DIFFERENCE OF TWO CUBES

• DIFFERENCE OF TWO SQUARES

• FACTORING BY GCF

• SUM OF TWO CUBES

Which number is both a perfect square and a perfect cube?

• 64

• 27

• 81

• 16