H a s i l d a r i ∫ sec ⁡ ( 1 − z ) tan ⁡ ( 1 − z ) d z a d a l a h . . . Hasil\ dari\int\sec\left(1-z\right)\tan\left(1-z\right)dz\ adalah\ ... H a s i l d a r i ∫ sec ( 1 − z ) tan ( 1 − z ) d z a d a l a h . . .

− sec ⁡ ( 1 − z ) + C -\sec\left(1-z\right)+C − sec ( 1 − z ) + C

sin ⁡ ( 1 − z ) + C \sin\left(1-z\right)+C sin ( 1 − z ) + C

cos ⁡ ( 1 − z ) + C \cos\left(1-z\right)+C cos ( 1 − z ) + C

sec ⁡ ( 1 − z ) + C \sec\left(1-z\right)+C sec ( 1 − z ) + C

− tan ⁡ ( 1 − z ) + C -\tan\left(1-z\right)+C − tan ( 1 − z ) + C

Kerja yang dilakukan oleh gaya F pada objek yang bergerak di sepanjang garis lurus dari a ke b adalah _____ jika F konstan, tetapi _____ jika F = F ( x ) F=F\left(x\right) F = F ( x ) merupakan variabel.

F ⋅ ( b − a ) ; ∫ a b F ( x ) d x F\cdot\left(b-a\right);\int_a^bF\left(x\right)dx F ⋅ ( b − a ) ; ∫ a b F ( x ) d x

∫ a b F d x ; ∫ a b F ( x ) d x \int_a^bFdx;\int_a^bF\left(x\right)dx ∫ a b F d x ; ∫ a b F ( x ) d x

F ⋅ ( b − a ) ; F ( x ) ⋅ ( b − a ) F\cdot\left(b-a\right);F\left(x\right)\cdot\left(b-a\right) F ⋅ ( b − a ) ; F ( x ) ⋅ ( b − a )

∫ a b F ⋅ ( b − a ) d x ; ∫ a b F ( x ) d x \int_a^bF\cdot\left(b-a\right)dx;\int_a^bF\left(x\right)dx ∫ a b F ⋅ ( b − a ) d x ; ∫ a b F ( x ) d x

∫ x n d x = \int_{ }^{ }x^{^n}dx= ∫ x n d x =

1 n + 1 x n + 1 + C \frac{1}{n+1}x^{n+1}+C n + 1 1 x n + 1 + C

1 n x n + 1 + C \frac{1}{n}x^{n+1}+C n 1 x n + 1 + C

n x n + 1 + C nx^{n+1}+C n x n + 1 + C

n x n − 1 + C nx^{n-1}+C n x n − 1 + C

∫ sin ⁡ ( 2 x ) d x = \int_{ }^{ }\sin(2x)dx= ∫ sin ( 2 x ) d x =

− 1 2 cos ⁡ ( 2 x ) + C -\frac{1}{2}\cos(2x)+C − 2 1 cos ( 2 x ) + C

1 2 cos ⁡ ( 2 x ) + C \frac{1}{2}\cos(2x)+C 2 1 cos ( 2 x ) + C

2 cos ⁡ ( 2 x ) + C 2\cos(2x)+C 2 cos ( 2 x ) + C

− 2 cos ⁡ ( 2 x ) + C -2\cos(2x)+C − 2 cos ( 2 x ) + C

∫ x n d x = \int_{ }^{ }x^{^n}dx= ∫ x n d x =

1 n + 1 x n + 1 + C \frac{1}{n+1}x^{n+1}+C n + 1 1 x n + 1 + C

1 n x n + 1 + C \frac{1}{n}x^{n+1}+C n 1 x n + 1 + C

n x n + 1 + C nx^{n+1}+C n x n + 1 + C

n x n − 1 + C nx^{n-1}+C n x n − 1 + C

∫ sin ⁡ 5 x . cos ⁡ 3 x d x \int\ \sin\ 5x\ .\ \cos\ 3x\ dx ∫ sin 5 x . cos 3 x d x

− 1 16 cos ⁡ 8 x − 1 4 cos ⁡ 2 x + C -\frac{1}{16}\ \cos\ 8x\ -\frac{1}{4}\ \cos\ 2x\ +C − 1 6 1 cos 8 x − 4 1 cos 2 x + C

1 8 sin ⁡ 8 x − 1 4 cos ⁡ 2 x \frac{1}{8}\sin\ 8x\ -\frac{1}{4}\ \cos\ 2x 8 1 sin 8 x − 4 1 cos 2 x

1 16 cos ⁡ 8 x + 1 4 sin ⁡ 2 x + C \frac{1}{16}\ \cos\ 8x\ +\ \frac{1}{4}\ \sin\ 2x\ +\ C 1 6 1 cos 8 x + 4 1 sin 2 x + C

1 4 sin ⁡ 8 x + 1 10 cos ⁡ 2 x + C \frac{1}{4}\sin\ 8x\ +\ \frac{1}{10}\ \cos\ 2x\ +\ C 4 1 sin 8 x + 1 0 1 cos 2 x + C

Jika R merupakan daerah antara kurva y = f(x) dan sumbu- x pada interval [ a, b ]. Jika f ( x ) ≥ 0 f\left(x\right)\ge0 f ( x ) ≥ 0 untuk seluruh x dalam [ a, b ], maka A ( R ) = _____, tetapi jika f ( x ) ≤ 0 f\left(x\right)\le0 f ( x ) ≤ 0 untuk seluruh x dalam [ a , b ], maka A ( R ) = ______

∫ a b f ( x ) d x ; − ∫ a b f ( x ) d x \int_a^bf\left(x\right)dx;-\int_a^bf\left(x\right)dx ∫ a b f ( x ) d x ; − ∫ a b f ( x ) d x

∫ a b f ( x ) d x ; ∫ a b f ( x ) d x \int_a^bf\left(x\right)dx;\int_a^bf\left(x\right)dx ∫ a b f ( x ) d x ; ∫ a b f ( x ) d x

∫ a b f ( x ) d x ; − ∫ b a f ( x ) d x \int_a^bf\left(x\right)dx;-\int_b^af\left(x\right)dx ∫ a b f ( x ) d x ; − ∫ b a f ( x ) d x

− ∫ a b f ( x ) d x ; − ∫ a b f ( x ) d x -\int_a^bf\left(x\right)dx;-\int_a^bf\left(x\right)dx − ∫ a b f ( x ) d x ; − ∫ a b f ( x ) d x

∫ sin ⁡ 2 x + cos ⁡ 3 x d x \int\sin\ 2x\ +\ \cos\ 3x\ dx ∫ sin 2 x + cos 3 x d x

− 1 2 cos ⁡ 2 x + 1 3 sin ⁡ 3 x + c -\frac{1}{2}\ \cos\ 2x\ \ +\ \frac{1}{3}\ \sin\ 3x\ +c − 2 1 cos 2 x + 3 1 sin 3 x + c

1 2 cos ⁡ 2 x − 1 3 sin ⁡ 3 x + C \frac{1}{2}\ \cos\ 2x\ -\frac{1}{3}\sin\ 3x\ +C 2 1 cos 2 x − 3 1 sin 3 x + C

− cos ⁡ 2 x + cos ⁡ 3 x + C -\cos\ 2x\ +\cos\ 3x\ +C − cos 2 x + cos 3 x + C

cos ⁡ 2 x − sin ⁡ 3 x + C \cos\ 2x\ -\sin\ 3x\ +C cos 2 x − sin 3 x + C

Hasil dari ∫ 0 2 π 1 − cos ⁡ x d x \int_0^{2\pi}\sqrt{1-\cos\ x}\ dx\ ∫ 0 2 π 1 − cos x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> d x adalah ....

2 2 2\sqrt{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 2 2 -2\ \sqrt{2} − 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 2 -\sqrt{2} − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 \sqrt{2} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

∫ sin ⁡ 3 x d x \int\ \ \sin\ 3x\ dx ∫ sin 3 x d x

− 1 3 cos ⁡ 3 x + C -\frac{1}{3}\ \cos\ 3x\ \ +C − 3 1 cos 3 x + C

1 3 cos ⁡ 3 x + C \frac{1}{3}\cos\ 3x\ \ +\ C 3 1 cos 3 x + C

cos ⁡ 3 x + C \cos\ 3x\ +C cos 3 x + C

sin ⁡ 1 3 x + C \sin\ \frac{1}{3}x\ \ +\ C sin 3 1 x + C

Integral Quiz

93 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Nilai dari $\int_1^3\left(x^2+\frac{1}{6}\right)dx= (a)$ (tulis dalam bilangan, jika pecahan tulis a/b)

2.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Kawat homogen terbentang pada sumbu-x antara $x=0$ dan $x=5$ akan setimbang pada $\overline{x}=$ _. Akan tetapi, jika kawat memiliki kerapatan $\delta\left(x\right)=1+x$ , titik setimbangnya berada pada $\overline{x}=$ _

$\int_0^5x\left(1+x\right)dx$

$\int_0^5\left(1+x\right)dx$

$\int_0^5xdx$

$\int_x^y\frac{1+x}{x}dx$

3.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Nilai dari $3\int_2^4\left(-x^2+6x-8\right)dx= (a)$ (tulis dalam bilangan, jika pecahan tulis a/b)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\int\left(\frac{4}{5}x^3-\ 4x^2+\frac{4}{x^2}-7\right)dx\ =\ ...$

$\frac{1}{5}x^4-\frac{4}{3}x^3-4x^{-1}-7x\ +\ c$

$\frac{1}{5}x^4-\frac{4}{3}x^3+4x^{-1}-7x+c$

$\frac{1}{5}x^4-\frac{4}{3}x^3-4x^{-1}-7+c$

$\frac{1}{5}x^4-8x^3-\frac{4}{3}x^2-7x+c$

$\frac{12}{5}x^4-8x^3-4x^{-1}-7x+c$

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\int_1^4(x^2-2x+2)dx=...$

18

16

14

12

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A

B

C

D

E

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

54

-54

27

-27

0

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\int_1^4(3\sqrt{x}-\frac{1}{\sqrt{x}})dx=...$

2

4

8

12

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

98 questions

Теор мех (Динамика 2)

Quiz

•

University

92 questions

2B H9 kloklezen

Quiz

•

1st Grade - University

93 questions

FALTA REDES EXAMEN CORREO

Quiz

•

1st Grade - University

90 questions

Algebra 1 Semester 1 Final Exam Review

Quiz

•

9th Grade - University

95 questions

куизиз

Quiz

•

University

89 questions

IoT and Web Development Quiz

Quiz

•

University

93 questions

Экономика

Quiz

•

University

93 questions

Mat oky

Quiz

•

University

Popular Resources on Wayground

10 questions

5.P.1.3 Distance/Time Graphs

Quiz

•

5th Grade

10 questions

Fire Drill

Quiz

•

2nd - 5th Grade

20 questions

Equivalent Fractions

Quiz

•

3rd Grade

22 questions

School Wide Vocab Group 1 Master

Quiz

•

6th - 8th Grade

20 questions

Main Idea and Details

Quiz

•

5th Grade

20 questions

Context Clues

Quiz

•

6th Grade

20 questions

Inferences

Quiz

•

4th Grade

12 questions

What makes Nebraska's government unique?

Quiz

•

4th - 5th Grade

Discover more resources for Mathematics

20 questions

10.4 Exponential Functions

Quiz

•

8th Grade - University

16 questions

Parallel, Perpendicular, and Intersecting Lines

Quiz

•

KG - Professional Dev...

20 questions

Circle Vocab

Quiz

•

KG - University

18 questions

Simplifying Radicals Practice

Quiz

•

University

22 questions

Parent Functions Homework

Quiz

•

9th Grade - University

7 questions

Introduction to Fractions

Interactive video

•

1st Grade - University

Integral

Nilai dari ∫13(x2+16)dx=....\int_1^3\left(x^2+\frac{1}{6}\right)dx= (a) ∫13​(x2+61​)dx=.... (tulis dalam bilangan, jika pecahan tulis a/b)

Kawat homogen terbentang pada sumbu-x antara x=0x=0x=0 dan x=5x=5x=5 akan setimbang pada x‾=\overline{x}=x= _____. Akan tetapi, jika kawat memiliki kerapatan δ(x)=1+x\delta\left(x\right)=1+xδ(x)=1+x , titik setimbangnya berada pada x‾=\overline{x}=x= _____

Nilai dari 3∫24(−x2+6x−8)dx=....3\int_2^4\left(-x^2+6x-8\right)dx= (a) 3∫24​(−x2+6x−8)dx=.... (tulis dalam bilangan, jika pecahan tulis a/b)

∫(45x3− 4x2+4x2−7)dx = ...\int\left(\frac{4}{5}x^3-\ 4x^2+\frac{4}{x^2}-7\right)dx\ =\ ...∫(54​x3− 4x2+x24​−7)dx = ...

∫14(x2−2x+2)dx=...\int_1^4(x^2-2x+2)dx=...∫14​(x2−2x+2)dx=...

∫14(3x−1x)dx=...\int_1^4(3\sqrt{x}-\frac{1}{\sqrt{x}})dx=...∫14​(3x​−x​1​)dx=...

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Nilai dari $\int_1^3\left(x^2+\frac{1}{6}\right)dx= (a)$ (tulis dalam bilangan, jika pecahan tulis a/b)

Kawat homogen terbentang pada sumbu-x antara $x=0$ dan $x=5$ akan setimbang pada $\overline{x}=$ _. Akan tetapi, jika kawat memiliki kerapatan $\delta\left(x\right)=1+x$ , titik setimbangnya berada pada $\overline{x}=$ _

Nilai dari $3\int_2^4\left(-x^2+6x-8\right)dx= (a)$ (tulis dalam bilangan, jika pecahan tulis a/b)

$\int\left(\frac{4}{5}x^3-\ 4x^2+\frac{4}{x^2}-7\right)dx\ =\ ...$

$\int_1^4(x^2-2x+2)dx=...$

$\int_1^4(3\sqrt{x}-\frac{1}{\sqrt{x}})dx=...$