sin 60 ° 60\degree 6 0 ° cos 30 ° 30\degree 3 0 ° - cos 60 ° 60\degree 6 0 ° sin 30 ° 30\degree 3 0 ° =...

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 2 \frac{1}{2}\sqrt{2} 2 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Sebuah tangga yang panjangnya 2 m disandarkan ke bagian paling atas sebuah tembok. Jika tinggi tembok = 3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> m dan α \alpha α merupakan sudut yang dibentuk oleh tangga dan tembok, maka α \alpha α =...

5 12 π \frac{5}{12}\pi 1 2 5 π

Jika sin A = 1 2 3 \ \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> dan A lancip, maka tan A = ...

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 3 3 \frac{1}{3}\sqrt{3} 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

sin 1 2 π \frac{1}{2}\pi 2 1 π . sin 1 3 π \frac{1}{3}\pi 3 1 π . sin 1 6 π \frac{1}{6}\pi 6 1 π =...

1 4 3 \frac{1}{4}\sqrt{3} 4 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 2 \frac{1}{2}\sqrt{2} 2 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 4 2 \frac{1}{4}\sqrt{2} 4 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Penyelesaian dari persamaan $$2\sin^2x-\sin x-1=0$$ untuk $$180\degree\le x\le360\degree$$ adalah ...

$$210\degree$$ dan $$330\degree$$

$$150\degree$$ dan $$180\degree$$

$$180\degree$$ dan $$210\degree$$

$$240\degree$$ dan $$270\degree$$

$$300\degree$$ dan $$330\degree$$

Himpunan penyelesaian dari tan ⁡ ⁡ ( x + 25 ° ) = tan ⁡ ⁡ 50 ° \tan⁡(x+25°)=\tan⁡50° tan ⁡ ( x + 2 5 ° ) = tan ⁡ 5 0 ° untuk 0 ° ≤ x ≤ 360 ° 0°≤x≤360° 0 ° ≤ x ≤ 3 6 0 ° adalah . . .

{ 25 ° , 205 ° } \left\{25°,205°\right\} { 2 5 ° , 2 0 5 ° }

{ 25 ° , 105 ° } \left\{25°,105°\right\} { 2 5 ° , 1 0 5 ° }

{ 25 ° , 305 ° } \left\{25°,305°\right\} { 2 5 ° , 3 0 5 ° }

{ 75 ° , 105 ° } \left\{75°,105°\right\} { 7 5 ° , 1 0 5 ° }

{ 75 ° , 205 ° } \left\{75°,205°\right\} { 7 5 ° , 2 0 5 ° }

diketahui cos 2x = cos 6 0 o 60^o 6 0 o , tentukan nilai x yang memenuhi untuk 0 o ≤ x ≤ 18 0 o 0^o\le x\le180^o 0 o ≤ x ≤ 1 8 0 o

3 0 o d a n 15 0 o 30^odan\ 150^o 3 0 o d a n 1 5 0 o

1 5 o d a n 3 0 o 15^odan\ 30^o 1 5 o d a n 3 0 o

6 0 o d a n 12 0 o 60^odan\ 120^o 6 0 o d a n 1 2 0 o

9 0 o d a n 18 0 o 90^o\ dan\ 180^o 9 0 o d a n 1 8 0 o

18 0 o d a n 36 0 o 180^odan\ 360^o 1 8 0 o d a n 3 6 0 o

Nilai dari Sin 60 adalah ...

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

1 3 3 \frac{1}{3}\sqrt{3} 3 1 3 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

3 \sqrt{3} 3 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

1 2 2 \frac{1}{2}\sqrt{2} 2 1 2 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

1 3 2 \frac{1}{3}\sqrt{2} 3 1 2 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

Untuk 0 ° ≤ x ≤ 360 ° 0\degree\le x\le360\degree 0 ° ≤ x ≤ 3 6 0 ° dalam persamaan 2 sin ⁡ x − 2 = 0 2\sin x-\sqrt{2}=0 2 sin x − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = 0 mempunyai himpunan penyelesaian ...

{ 45 ° , 135 ° } \left\{45\degree,135\degree\right\} { 4 5 ° , 1 3 5 ° }

{ 45 ° , 315 ° } \left\{45\degree,315\degree\right\} { 4 5 ° , 3 1 5 ° }

{ 135 ° , 225 ° } \left\{135\degree,225\degree\right\} { 1 3 5 ° , 2 2 5 ° }

{ 45 ° , 135 ° , 225 ° } \left\{45\degree,135\degree,225\degree\right\} { 4 5 ° , 1 3 5 ° , 2 2 5 ° }

{ 45 ° , 135 ° , 225 ° , 315 ° } \left\{45\degree,135\degree,225\degree,315\degree\right\} { 4 5 ° , 1 3 5 ° , 2 2 5 ° , 3 1 5 ° }

Trigonometri

Quiz

•

Mathematics

•

2nd Grade

•

Practice Problem

•

Hard

Nesy Widyastuti

FREE Resource

120 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Manakah pernyataan berikut yang salah ....

\cos\alpha=\frac{samping}{miring}

$\tan\alpha=\frac{depan}{samping}$

$\operatorname{cotan}\alpha=\frac{samping}{miring}$

$\sin\alpha=\frac{depan}{miring}$

$\sec\alpha=\frac{miring}{depan}$

2.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Nilai x pada interval $0\degree\le x\le360\degree$ yang memenuhi persamaan tan x = - 1

$0\degree$

$360\degree$

$315\degree$

$270\degree$

$135\degree$

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trgionometri disebut ....

cosecan

sinus

cosinus

secan

tangen

4.

MULTIPLE CHOICE QUESTION

30 sec • 10 pts

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trigonometri disebut...

Sinus

Cosinus

Tangen

Cotangen

Cosecan

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Keliling suatu segienam beraturan adalah 72 cm. Luas segi enam tersebut adalah ...

432 √3 cm²

432 cm²

216 √3 cm²

216 √2 cm²

216 cm²

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

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Trigonometri

120 questions

Manakah pernyataan berikut yang salah ....

Nilai x pada interval $0\degree\le x\le360\degree$ yang memenuhi persamaan tan x = - 1

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trgionometri disebut ....

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trigonometri disebut...

Keliling suatu segienam beraturan adalah 72 cm. Luas segi enam tersebut adalah ...

Pernyataan yang benar berikut ini adalah ....

Pada segitiga lancip ABC diketahui panjang sisi AC = 4cm, AB = 5 cm, dan cos B =4/5 ,
maka cos C = …

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Popular Resources on Wayground

Discover more resources for Mathematics

Trigonometri

120 questions

Manakah pernyataan berikut yang salah ....

Nilai x pada interval 0°≤x≤360°0\degree\le x\le360\degree0°≤x≤360° yang memenuhi persamaan tan x = - 1

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trgionometri disebut ....

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trigonometri disebut...

Keliling suatu segienam beraturan adalah 72 cm. Luas segi enam tersebut adalah ...

Pernyataan yang benar berikut ini adalah ....

Pada segitiga lancip ABC diketahui panjang sisi AC = 4cm, AB = 5 cm, dan cos B =4/5 , maka cos C = …

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

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Nilai x pada interval $0\degree\le x\le360\degree$ yang memenuhi persamaan tan x = - 1

Pada segitiga lancip ABC diketahui panjang sisi AC = 4cm, AB = 5 cm, dan cos B =4/5 ,
maka cos C = …