ELECTROSTATIC 1.3-1.4

$$F\ =\ k\ \frac{Qq}{r}$$

$$V=\frac{kQq}{r^2}$$

$$E=\frac{kQ}{r}$$

$$V=\frac{kQ}{r}$$

Electric potential is a scalar quantity.

The unit for electric potential is J C^-1 and V

Equipotential surface is always parallel to E lines.

Electric potential is decreasing in the direction of E.

F $$\rightarrow$$ E

A $$\rightarrow$$ D

C $$\rightarrow$$ F

D $$\rightarrow$$ C

Electric field strength, E

Electrostatic force, F

Electric potential

Charge

positive

negative

a $$=\ \frac{qm}{E}$$

a $$=\frac{qE}{m}$$

a $$=\frac{Em}{q}$$

a $$=\frac{F}{q}$$