3 ( x + 5 ) 1 2 − 6 = 0 3\left(x+5\right)^{\frac{1}{2}}-6=0 3 ( x + 5 ) 2 1 − 6 = 0

2 − 5 \sqrt{2}-5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 5

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Math

Algebra

Solving Square Root Equations

solving square root equations

Authored by Neetu Patel

Mathematics

9th - 12th Grade

Used 2+ times

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15 questions

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FILL IN THE BLANKS QUESTION

15 mins • 1 pt

(a)

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

$\left(x+2\right)^{\frac{1}{2}}+3=7$

(a)

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

$\sqrt{3x-11}=\sqrt{5-x}$

(a)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$2\left(x-7\right)^{\frac{1}{2}}-3=1$

no solution

MULTIPLE CHOICE QUESTION

10 mins • 6 pts

Determine the equation for the graph.

$y=2\sqrt{x}-4$

$y=-\sqrt{x-4}$

$y=2\sqrt{x}$

$y=2\sqrt{x}+4$

MULTIPLE CHOICE QUESTION

10 mins • 6 pts

Which of these equations shifts a radical equation right 5 units and down one unit?

$y=\sqrt{x-5}-1$

$y=\sqrt{x+5}-1$

$y=\sqrt{x-5}+1$

$y=\sqrt{x+5}+1$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$-12=-6\sqrt[]{x+4}$

x = 0

x = 1

x = 46

x = 4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$3\left(x+5\right)^{\frac{1}{2}}-6=0$

-3

-1

$\sqrt{2}-5$

no solution

MULTIPLE CHOICE QUESTION

10 mins • 6 pts

$\sqrt{x+13}-8=-2$

no solution

$\sqrt{10}-13$

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solving square root equations

(a)

(x+2)12+3=7\left(x+2\right)^{\frac{1}{2}}+3=7(x+2)21​+3=7 (a)

3x−11=5−x\sqrt{3x-11}=\sqrt{5-x}3x−11​=5−x​ (a)

2(x−7)12−3=12\left(x-7\right)^{\frac{1}{2}}-3=12(x−7)21​−3=1

Determine the equation for the graph.

Which of these equations shifts a radical equation right 5 units and down one unit?

−12=−6x+4-12=-6\sqrt[]{x+4}−12=−6x+4​

3(x+5)12−6=03\left(x+5\right)^{\frac{1}{2}}-6=03(x+5)21​−6=0

x+13−8=−2\sqrt{x+13}-8=-2x+13​−8=−2

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$\left(x+2\right)^{\frac{1}{2}}+3=7$

(a)

$\sqrt{3x-11}=\sqrt{5-x}$

(a)

$2\left(x-7\right)^{\frac{1}{2}}-3=1$

$-12=-6\sqrt[]{x+4}$

$3\left(x+5\right)^{\frac{1}{2}}-6=0$

$\sqrt{x+13}-8=-2$