Q10 MCQ

Determine the Q10 value from the data.

• 2.00

• 1.44

• 1.25

• 3.00

Answer explanation

Using the formula, calculate the Q10 between each data set and find the average.

Determine the Q10 value from the data.

• 1.75

• 2

• 1.54

• 2.25

Determine the Q10 value from the data.

• 2.04

• 1.49

• 2.21

• 1.54

What are the log R values for the temperatures 298K and 313K?

• 298K: 2.474

  313K: 2.496

• 298K: 2.467

  313K: 2.496

• 298K: 1.806

  313K: 1.931

• 298K: 1.769

  313K: 1.931

If Q10 for an enzyme E is 2.00, what is the rate of enzyme activity at 20°C and 40°C?

• 20°C: 26

  40°C: 104

• 20°C: 23

  40°C: 43

• 20°C: 26

  40°C: 52

• 13. The rate will not change.

Answer explanation

Q10 = rate of reaction at (T + 10˚C)/rate of reaction at T˚C

At 20°C: 2 = x/13

13 * 2 = x

26 = x

At 30°C: 2 = x/26

26 * 2 = x

52 = x

At 40°C: 2 = x/52

52 * 2 = x

104 = x

From the graph, determine the Q10 of this reaction.

• Q10 = 1.5

• Q10 = 2.5

• Q10 = 3

• Q10 = 2

What are the Q10 values for each line?

• Red: 4

  Green: 3

  Orange: 2

  Blue: 1

• Red: 3

  Green: 2

  Orange: 0

  Blue: 0.5

• Red: 3

  Green: 2

  Orange: 1

  Blue: 0.5

• Red: 3.5

  Green: 2

  Orange: 1

  Blue: 0

Given the two sets of graph coordinates: (1.40, 0.98) and (3.40, 1.58), determine the Q10 value.

• 2.153

• 1.995

• 2.135

• 1.890

Answer explanation

Q10 = antilog of the slope (gradient)

Calculate gradient of the line using the two points

Recall: y2 - y1/x2 - x1

Find antilog of the gradient.

If Q10 = 2, then an enzymatic reaction that takes place at a given rate at 5°C would take place approximately how many times faster at 25°C?

• Twenty times

• Eight times

• Four times

• Three times

• Two times