HGE 1110 ▬ STATISTICS AND PROBABILITY ▬ Q3 - PETA7

Thirty-two percent of adult Internet users have purchased products or services online. For a random sample of 200 adult Internet users. Find the mean, variance, and standard deviation for the number who have purchased goods or services online.

Find the mean.

• 43.52

• 64

• 6.60

• 6400

Thirty-two percent of adult Internet users have purchased products or services online. For a random sample of 200 adult Internet users. Find the mean, variance, and standard deviation for the number who have purchased goods or services online. 

Find the variance.

• 6.60

• 10.50

• 43.52

• 64

Thirty-two percent of adult Internet users have purchased products or services online. For a random sample of 200 adult Internet users. Find the mean, variance, and standard deviation for the number who have purchased goods or services online.

Find the standard deviation.

• 64

• 43.52

• 1893.99

• 6.60

Let X be a binomial random variable that is binomially distributed with a mean of 8 and a variance of 4. Find n and p.

(a)  

Let X be a binomial random variable that is binomially distributed with a mean of 81 and a variance of 54. Find n and p.

(a)  

Let X be a binomial random variable that is binomially distributed with a mean of 18 and a variance of 9. Find n and p.

(a)  

Let X be a binomial random variable that is binomially distributed with a mean of 18 and a variance of 6. Find n and p.

(a)  

Eighty-five percent of Filipinos favor spending government money to develop alternative sources of fuel for automobiles. For a random sample of 120 Filipinos, find the mean, variance, and standard deviation for the number who favor government spending on alternative fuels.

Find the mean, variance, and standard deviation.

• mean = 102

  variance = 15.3

  sd = 3.91

• mean = 3.91

  variance = 102

  sd = 15.3

• mean = 15.3

  variance = 3.91

  sd = 102

Find the mean, variance, and standard deviation for each of the values of n and p when the conditions for the binomial distribution are met.

n =100, p = 0.75

Find the mean, variance, and standard deviation.

• mean = 18.75

  variance = 75

  sd = 4.33

• mean = 4.33

  variance = 18.75

  sd = 75

• mean = 75

  variance = 18.75

  sd = 4.33

Find the mean, variance, and standard deviation for each of the values of n and p when the conditions for the binomial distribution are met.

n =36, p = 1/6

Find the mean, variance, and standard deviation.

• mean = 2.24

  variance = 6

  sd = 5

• mean = 5

  variance = 2.24

  sd = 6

• mean = 6

  variance = 5

  sd = 2.24