MATHEMATICS 10- Summative Quiz

Which of the following is an impossible events?

• Choosing an odd number from 1 to 10.

• Getting an even number after rolling a die

• Choosing a white marbles from a jar of 25 green marbles

• None of the above

Tags

CCSS.7.SP.C.5

The probability that a student plays basketball is 0.54, and the probability that a student likes pizza is 0.30. What is the probability that a student selected at random plays basketball and likes pizza?

• 0.162

• . 0.216

• . 0.612

• 0.840

In rolling 2 dice, what is the probability that you can get a quotient of 1?

• 1/6

• 30/ 36

• 5/ 6

• 1

Tags

CCSS.HSS.MD.B.6

CCSS.HSS.MD.B.7

.If there is 70% chance that Mike will buy an I-phone, 40% chance that he will buy a TV, and 28% chance that he will buy an I-phone and a TV, what is the probability that he will buy an Iphone or a TV?

• 28%

• 68%

• 70%

• 82%

Tags

CCSS.HSS.CP.B.7

What kind of mathematics that’s deals with the game of chances?

• Statistics

• Probability

• Algebra

• Trigonometry

Tags

CCSS.HSS.CP.A.3

CCSS.HSS.CP.A.5

Two cards are drawn from a deck of 52 cards. Find the probability of drawing a queen first followed by nine if the first card is not replaced.

• 1/169

• 2/169

• 4/663

• 8/663

The probabilities of three students Coleen, Mark and Makoy winning the poster making contest are 2 , 1 , and 1, respectively . What is the probability that Coleen or Makoy wins?

• 1 /40

• 15 /35

• 13/ 40

• 17 /35

Tags

CCSS.HSS.CP.B.7

A card is drawn at random from a standard deck of cards. What is the probability of drawing an ace or face cards?

• 16/ 52

• 4/ 52

• 12 /52

• 14 /52

Tags

CCSS.HSS.CP.B.7

What event are consist of two events that are disjoint events and have no common elements?

• Intersection of Events

• Mutually Exclusive Event

• Compound Events

• Simple Event

Tags

CCSS.HSS.CP.A.1

What is the formula for the probability of the union of two non-mutually exclusive events to happen ?

• P(AUB)= P(A)+ P(B)

• P(A∩B) = P(A)- P(B)

• P(AUB)= P(A)+ P(B)-P(A∩B)

• P(A∩B)= P(A)+ P(B)-P(AUB)

Tags

CCSS.HSS.CP.B.7