BIO Chapter 13 & 14

1. In some plants, a true-breeding, red flowered strain gives all pink flowers when crossed with a white flowered strain: C°C® (red) X c"CW (white)--> c°C™ (pink). Flower position can be axial or

terminal where A= axial and a = terminal. What will be the ratios of genotypes and

phenotypes of the F1 generation resulting from the following cross :

• AACRCR x aaCWCW

• F1 genotype

  AaCRCW

• Phenotype

  Axial & PINK

• AACWCW x aaCRCR

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In some plants, a true-breeding, red flowered strain gives all pink flowers when crossed with a white flowered strain: C°C® (red) X c"CW (white)--> c°C™ (pink). Flower position can be axial or

terminal where A= axial and a = terminal. (PART 2)

What will be the ratios in the F2 generation?

• F1 G Ratios

  4 AaCRCW

  2AaCRCR

  2AACRCW

  2aaCRCW

  CAaCWCW

• 1 AACRCR

  1 aaCRCR

  1 AACWCW

  1 aaCWCW

• F2 ratios

  6:3:2:1:1

• NOT THE ANSwer lol

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If a plant that is heterozygous for all three characters is allowed to self fertilize, what proportion of the offspring would you expect to be as follows? (note: use the rules of probability instead of a huge punnett square). (note: refer to page 259)

• Homozygous for the three dominant traits: ¼ × ¼ × ¼ = 1/64

• Homozygous for the three recessive traits: 1/64

• Heterozygous for all three characters: ½×½×½=1/8

• Homozygous for axial and tall, heterozygous for seed shape ¼×¼×½=1/32

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In sesame plants, the one-pod condition (P) is dominant to the three-pod condition (p), and normal leaf (L) is dominant to wrinkled leaf(I). Pod type and leaf type are inherited independently. Determine the genotypes for the two parents producing the following offspring.

a. 150 one-pod, normal leaf:147 one-pod, wrinkled leaf: 51 three-pod, normal leaf: 48 three-pod, wrinkled leaf

• PPll x PPLL

• PpLl x PpLl

• PpLi x Ppll

• pP x LL

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In sesame plants, the one-pod condition (P) is dominant to the three-pod condition (p), and normal leaf (L) is dominant to wrinkled leaf(I). Pod type and leaf type are inherited independently. Determine the genotypes for the two parents producing the following offspring.

b. 223 one-pod, normal leaf: 72 one-pod, wrinkled leaf: 76 three-pod, normal leaf: 27 three-pod, wrinkled leaf

• LL x PP

• PpLl x PpLl

• PP x LL

• Idk

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A man with type A blood marries a woman with type B blood. Their child has type O blood. What are the genotypes of these individuals? What other genotypes, and in what frequencies, would you expect in offspring from this marriage?

• Idk

• Idk

• idk

• 1/4 IA IB

  1/4 IA i

  1/4 IB i

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Phenylketonuria(PKU) is an inherited disease caused by a recessive allele. If a women and her husband, who are both carriers, have three children, what is the probability of each of the following?

All three children are of normal phenotype?

• Idk

• ¾ × ¾ × ¾ = 27/64

• Idk

• Idk

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Phenylketonuria(PKU) is an inherited disease caused by a recessive allele. If a women and her husband, who are both carriers, have three children, what is the probability of each of the following?

All three children have the disease.

• hard

• Study

• Nope

• ¼ × ¼ × ¼ = 1/64

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The genotype of F individuals in a tetrahybrid cross is AaBbCcDd. Assuming independent assortment of these four genes, what are the probabilities that F offspring will have the following genotypes?

• Aabbcedd ½ × ¼ × ¼ × ¼ = 1/128

  AaBbCcDd ½×½×½×½ = 1/16

• AABBCCDD ¼ × ¼ × ¼ × ¼ = 1/256

  AaBBccDd½×¼×¼×½=1/64

  AaBBCCdd ½ × ¼ × ¼ × ¼ = 1/128

• hi

• Like it

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In 1981, a stray black cat with unusual rounded, curled-black ears was adopted by a family in California. Hundreds of descendants of the cat have since been born, and cat fanciers hope to develop the curl cat into a show breed. Suppose you owned the first curl cat and wanted to develop a true-breeding variety. How would you determine whether the curl allele is dominant or recessive? How would you obtain true-breeding curl cats? How could you be sure they are true-breeding? Your answer can be bulleted or paragraph form.

• Shut it

• Nope

• Matings of the original mutant cat with true-breeding noncurl cats will produce both curl and noncurl F1 offspring if the curl allele is recessive. You would obtain some true-breeding offspring homozygous for the curl allele from matings between the F1 cats resulting from the original curl X noncurl crosses whether the curl trait is dominant or recessive. You know that cats are true breeding when curl X curl matings produce only curl offspring. As it turns out, the allele that causes curled ears is dominant.

• I’m tired

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