
Hess's law quiz
Assessment
•
Martha Borra
•
Chemistry
•
10th Grade
•
1 plays
•
Medium
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16 questions
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1.
MULTIPLE CHOICE
30 sec • 1 pt
Using the equations below:
C(s) + O2(g) → CO2(g) ∆H = –390 kJ
Mn(s) + O2(g) → MnO2(s) ∆H = –520 kJ
what is ∆H (in kJ) for the following reaction?
MnO2(s) + C(s) → Mn(s) + CO2(g)
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2.
MULTIPLE CHOICE
30 sec • 1 pt
Using the equations below
Cu(s) + 1/2O2(g) → CuO(s) ∆H = –156 kJ
2Cu(s) + O2(g) → Cu2O(s) ∆H = –170 kJ
what is the value of ∆H (in kJ) for the following reaction?
2CuO(s) → Cu2O(s) + 1/2O2(g)
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3.
MULTIPLE CHOICE
30 sec • 1 pt
Consider the following equations.
Mg(s) + O2(g) → MgO(s) ∆H = –602 kJ
H2(g) + O2(g) → H2O(g) ∆H = –242 kJ
What is the ∆H value (in kJ) for the following reaction?
MgO(s) + H2(g) → Mg(s) + H2O(g)
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4.
MULTIPLE CHOICE
30 sec • 1 pt
The following equations show the oxidation of carbon and carbon monoxide to carbon dioxide.
C(s) +O2(g) → CO2(g) ΔH = –x kJ mol–1
CO(g) + O2(g) → CO2(g) ΔH = –y kJ mol–1
What is the enthalpy change, in kJ mol–1, for the oxidation of carbon to carbon monoxide?
C(s) + O2(g) → CO(g)
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5.
MULTIPLE SELECT
30 sec • 1 pt
Which of the following statements are true for the reaction:
SO2(g) + 1/2O2(g) ↔ SO3(g)
ΔH = –92 kJ mol-1
Where ↔ indicates that the reaction can proceed in the forward and the reverse direction.
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6.
MULTIPLE CHOICE
30 sec • 1 pt
The standard enthalpy change of formation values of two oxides of phosphorus are:
P4(s) + 3O2(g) → P4O6(s) ΔHf = –1600 kJ mol–1
P4(s) + 5O2(g) → P4O10(s) ΔHf = –3000 kJ mol–1
What is the enthalpy change, in kJ mol–1, for the reaction below?
P4O6(s) + 2O2(g) → P4O10(s)
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7.
MULTIPLE CHOICE
20 sec • 1 pt
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8.
MULTIPLE CHOICE
20 sec • 1 pt
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9.
MULTIPLE CHOICE
30 sec • 1 pt
A chemical reaction that requires energy is a(n)
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10.
MULTIPLE CHOICE
2 mins • 1 pt
The enthalpies of combustion of C(s), H2(g) and C4H9OH(l) (in kJmol-1) are as follows C(s) + O2(g) ---> CO2(g) ∆H=a H2(g) + ½O2(g) ---> H2O(l) ∆H=b C4H9OH(l) + 6O2(g) ---> 4CO2(g) + 5H2O(l) ∆H=c
What is the enthalpy change for the reaction shown below? 4C(g) + 5H2(l) + ½O2(g) ---> C4H9OH(l)
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