DDSQL2-DP8-P10

DDSQL2-DP8-P10

University

15 Qs

quiz-placeholder

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DDSQL2-DP8-P10

DDSQL2-DP8-P10

Assessment

Quiz

Computers

University

Hard

Created by

Roni salambue

Used 1+ times

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which group function would you use to display the average price of all products in the PRODUCTS table?

MAX

SUM

COUNT

AVG

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

You need to calculate the average salary of employees in each department. Which group function will you use?

AVERAGE

MEAN

MEAN

AVG

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which group function would you use to display the highest salary value in the EMPLOYEES table?

MAX

MIN

COUNT

AVG

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

You need to calculate the standard deviation for the cost of products produced in the Birmingham facility. Which group function will you use?

VARIANCE

STDEV

VAR_SAMP

STDDEV

5.

MULTIPLE SELECT QUESTION

1 min • 1 pt

The VENDORS table contains these columns:

VENDOR_ID NUMBER Primary Key NAME VARCHAR2(30) LOCATION_ID NUMBER ORDER_DT DATE ORDER_AMOUNT NUMBER(8,2)

Which two clauses represent valid uses of aggregate functions for this table?

(Choose all correct answers)

SELECT SUM(order_dt)

FROM MAX(order_dt)

WHERE MAX(order_dt) = order_dt

SELECT SUM(order_amount)

SELECT MIN(AVG(order_amount))

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given the following data in the employees table (employee_id, salary, commission_pct)

DATA: (143, 2600, null 144, 2500, null 149, 10500, .2 174, 11000, .3 176, 8600, .2 178, 7000, .15)

What is the result of the following statement:

SELECT SUM(commission_pct), COUNT(salary) FROM employees WHERE employee_id IN( 143,144,149,174,176,178);

SUM = 1.85 and COUNT =4

SUM = .85 and COUNT = 4

SUM = .85 and COUNT = 6

SUM = 1.85 and COUNT = 6

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given the following data in the employees table (employee_id, salary, commission_pct)

DATA: (143, 2600, null 144, 2500, null 149, 10500, .2 174, 11000, .3 176, 8600, .2 178, 7000, .15)

What is the result of the following statement:

SELECT AVG(commission_pct) FROM employees WHERE employee_id IN( 143,144,149,174,176,178);

0.2125

This statement is invalid

0.0425

1.2125

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