Search Header Logo

NECTS- Code Debugging Elimination Round

Authored by Rajendra Rajendra

Computers

Professional Development

Used 12+ times

NECTS- Code Debugging Elimination Round
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 2 pts

    

--This Question Carries 2 Marks--

void main() {

char c[ ] = "IATEBURGER";

int x= ; int y= ; char *p = c;

printf("%s",p+p[x]-p[y]); }

  What are the missing values of x and y to print output? BURGER

a) x=1,y=1

b) x=3 ,y=3

c) x=1 ,y=3

d) x=3 ,y=1

2.

MULTIPLE CHOICE QUESTION

3 mins • 3 pts

--This Question Carries 3 Marks--

int main() {

    int arr[] = {1, 7, 3, 1, 7, 4, 3};

    int n = sizeof(arr) / sizeof(arr[0]);

    int result = 0;

        for (int i = 0; i < n; i++) {

        result =

    }

    int missingNumber = result;

    printf("The missing number is: %d\n", missingNumber);

    return 0;

}

In the above  code add the missing code of result to get the distinct element of the array.

a)       result &=arr[I];

b)      result ^=arr[I];

c)       result &&=arr[I];

d)      result |=arr[I];

3.

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

--This Question Carries 5 Marks--

int r(){

static int num=7;

return num--; }

int main() {

for (r();r();r())

printf("%d",r());

return 0; }

a)       52

b)      51

c)       49

d)      Error

4.

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

Media Image

a)       arr[i+1] = arr[i]

b)      arr[j] = arr[j+1]

c)       arr[i] = arr[i+1]

d)      arr[j+1] = arr[j]

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

a)       set(array_nums)

b)      list(array_nums)

c)       dict(array_nums)

d)      tuple(array_nums)

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Microsoft

Continue with Microsoft

or continue with

Facebook

Facebook

Apple

Apple

Others

Others

By signing up, you agree to our Terms of Service & Privacy Policy

Already have an account?