Which construction is shown?

• Congruent Segments

• Congruent Angles

• Perpendicular Bisector

• Angle Bisector

Tags

MA.912.GR.5.1

Which construction is shown?

• Congruent segments

• Congruent angles

• Perpendicular bisector

• Angle bisector

Tags

MA.912.GR.5.2

Which construction is shown?

• Congruent segments

• Congruent angles

• Perpendicular bisector

• Angle bisector

Tags

MA.912.GR.5.1

Which construction is shown?

• Congruent segments

• Congruent angles

• Perpendicular bisector

• Angle bisector

Tags

MA.912.GR.5.2

What is the result of the construction?

• AB is parallel to MN

• AB is congruent to MN

• M is the midpoint of MN

• AB is perpendicular to MN

Tags

MA.912.GR.5.1

What is the result of the construction?

• UT is parallel to DS

• D is the midpoint of SN

• ∠TUV and ∠SDN are perpendicular

• ∠TUV ≅ ∠SDN

Tags

MA.912.GR.5.1

What is the result of the construction?

• ∠XYZ ≅ ∠XYM

• M is the midpoint of ∠XYZ

• ∠XYM ≅ ∠ZYM

• XY is perpendicular to YZ

Tags

MA.912.GR.5.2

What is the result of the construction?

• PM ≅ QM

• The two lines are parallel.

• Each arc is a bisector.

• PQ ≅ QM

Tags

MA.912.GR.5.2

Put the steps in order to draw a segment congruent to existing segment AB.

• Without changing the width, place the compass point on point C and draw an arc.

• Name the intersection of the line and the arc D. CD is the congruent segment.

• Draw a point separate from segment AB and name it C.

• Open your compass to the width of AB.

• Use a straightedge to draw a line between point C and the arc.

Answer explanation

Tags

MA.912.GR.5.1

Put the steps in order to construct the perpendicular bisector of segment AB.

• Set the compass point on Point A and open it more than halfway across AB.

• Name the intersections of the arcs C and D.

• Use a straightedge to draw the line through point C and D and label the point of intersection P.

• Place the compass point on Point B without changing the width, and repeat Step 2 to create another arc that is centered on B.

• Use the existing compass width to draw an arc that goes above and below AB that is centered on A.

Tags

MA.912.GR.5.2