SCI 101 DrG week 10 Vehicle Dynamics

Kinetic energy = ½ (mass) x (velocity)2 

Convert 4000 pounds to kg 1814.36948         X pounds / 2.2046 = Y kg

Convert 100 mph to m/s 44.704                     mph X .44704 = m/s

Determine the kinetic energy of 4000-pound car going 120 miles per hour.

• 1.8 million joules

• 3..6 million joules

• 2.6 joules

• 2.6 million joules

Tags

NGSS.HS-PS3-1

Kinetic energy = ½ (mass) x (velocity)2 

Convert 4000 pounds to kg 1814.36948         X pounds / 2.2046 = Y kg

Convert 100 mph to m/s 44.704                     mph X .44704 = m/s

Determine the kinetic energy of 3000-pound car going 80 miles per hour. (round up)

• .9 million joules

• 9 million joules

• 1.9 million joules

• .009 million joules

Tags

NGSS.HS-PS3-1

Kinetic energy = ½ (mass) x (velocity)2 

Convert 4000 pounds to kg 1814.36948         X pounds / 2.2046 = Y kg

Convert 100 mph to m/s 44.704                     mph X .44704 = m/s

Determine the kinetic energy of 3000-pound car going 120 miles per hour. (round up)

• 2 million joules

• 3 million joules

• 1 million joules

• 5 million joules

Tags

NGSS.HS-PS3-2

Centrifugal Force = (mass) X (velocity)2/ radius of turn (in meters)

Convert pounds to kg (1814.36948).  Use this formula X pounds / 2.2046 = Y kg

Convert mph to m/s (44.704).   Use this formula mph X .44704 = m/s

1 foot = .3048 meters (Round to nearest whole number).

Find the centrifugal force for a 4000-pound car going 80 miles/hour around a 5-foot radius turn. (round up)

• .8 million N

• 1 million N

• 2 million N

• 05 million N

Tags

NGSS.HS-PS2-1

1.46666667 ft/s in 1 mph                           9.8 m/s² = 32.8084 ft/s ²

 

V = 50 km/hr is (31) mph                            1 mph  X .44704=  m/s

 

31 mph X .44704 = 13.86 m/s

13.86/.3048 = 45.57 ft/sec (reaction Time)

 

Stopping distance formula

Sd = v² / (2 X µ X g)

1.       Amy, a driver in a car on a residential street with 0% slope is traveling at 50 km (31 mph) per hour. Amy is texting. She put her brakes on when she sees a stop sign with a slower than normal reaction time of 2 seconds. The drag coefficient of friction between the tires and the road is µ = 0.3 because it is raining. What is the stopping distance of the car?

• 107.07 feet

• 152.54 feet

• 45.47 feet

• 61.6 feet

Tags

NGSS.HS-PS2-1