TrigoNometric Ratios

TrigoNometric Ratios

9th - 12th Grade

15 Qs

quiz-placeholder

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TrigoNometric Ratios

TrigoNometric Ratios

Assessment

Quiz

Mathematics

9th - 12th Grade

Medium

CCSS
HSG.SRT.C.6, HSG.SRT.C.8, 8.G.A.5

+3

Standards-aligned

Created by

AIRIL Moe

Used 3+ times

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the SINE ratio of any angle in a right triangle

adjacenthypotenuse\frac{\text{adjacent}}{\text{hypotenuse}}

oppositehypotenuse\frac{\text{opposite}}{hypotenuse}

oppositeadjacent\frac{\text{opposite}}{\text{adjacent}}

hypotenuseopposite\frac{\text{hypotenuse}}{\text{opposite}}

Tags

CCSS.HSG.SRT.C.6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the COSINE ratio of any angle in a right triangle

adjacenthypotenuse\frac{\text{adjacent}}{\text{hypotenuse}}

oppositehypotenuse\frac{\text{opposite}}{hypotenuse}

oppositeadjacent\frac{\text{opposite}}{\text{adjacent}}

hypotenuseopposite\frac{\text{hypotenuse}}{\text{opposite}}

Tags

CCSS.HSG.SRT.C.6

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the TANGENT ratio of any angle in a right triangle

adjacenthypotenuse\frac{\text{adjacent}}{\text{hypotenuse}}

oppositehypotenuse\frac{\text{opposite}}{hypotenuse}

oppositeadjacent\frac{\text{opposite}}{\text{adjacent}}

hypotenuseopposite\frac{\text{hypotenuse}}{\text{opposite}}

Tags

CCSS.HSG.SRT.C.6

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

"θ" is used to represent an unknown ____________.

angle

side

hypotenuse

Tags

CCSS.8.G.A.5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is the correct acronym to help remember the three trigonometric ratios

SOH COH TOA

SAH COH TOA

SOH CAH TOH

SOH CAH TOA

Tags

CCSS.HSG.SRT.C.6

6.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

Media Image

What is sin(A) ?

1237\frac{12}{37}

1235\frac{12}{35}

3537\frac{35}{37}

3512\frac{35}{12}

Tags

CCSS.HSG.SRT.C.6

7.

MULTIPLE CHOICE QUESTION

5 mins • 2 pts

Media Image

In the diagram, S is the midpoint of PQ. If  tanx=25\tan x=\frac{2}{5}  and  PR=10 cmPR=10\ cm  , then  tany=\tan y=  

 58\frac{5}{8}  

 45\frac{4}{5}  

 54\frac{5}{4}  

 52\frac{5}{2}  

Tags

CCSS.HSG.CO.C.10

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