RASIO TRIGONOMETRI PADA SEGITIGA SIKU-SIKU

RASIO TRIGONOMETRI PADA SEGITIGA SIKU-SIKU

10th Grade

10 Qs

quiz-placeholder

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RASIO TRIGONOMETRI PADA SEGITIGA SIKU-SIKU

RASIO TRIGONOMETRI PADA SEGITIGA SIKU-SIKU

Assessment

Quiz

Mathematics

10th Grade

Hard

CCSS
HSG.SRT.C.6, HSF.TF.A.2

Standards-aligned

Created by

Mahendra Septiawan

Used 60+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Nilai dari sec γ\gamma  adalah...

 2029\frac{20}{29}  

 2129\frac{21}{29}  

 2921\frac{29}{21}  

 2920\frac{29}{20}  

 2021\frac{20}{21}  

Tags

CCSS.HSG.SRT.C.6

2.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Fungsi trigonometri yang merupakan kebalikan dari sinus adalah ....

kosinus (cos)

tangent (tan)

cotangen (cot)

secan (sec)

cosecan (cosec)

Tags

CCSS.HSF.TF.A.2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Untuk gambar di atas, perbandingan c dan a (c/a) disebut ....

secan (sec)

cosecan (cosec)

cotangen (cot)

tangen (tan)

Tags

CCSS.HSG.SRT.C.6

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Besar sudut  114πrad1\frac{1}{4}\pi rad  sama dengan ...

 205°205^{\degree}  

 215°215^{\degree}  

 225°225^{\degree}  

 235°235^{\degree}  

 245°245^{\degree}  

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Besar sudut  72°72^{\degree} sama dengan ... rad

 15π\frac{1}{5}\pi  

 25π\frac{2}{5}\pi  

 23π\frac{2}{3}\pi  

 34π\frac{3}{4}\pi  

 56π\frac{5}{6}\pi  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diketahui segitiga KLM memiliki koordinat K(-5,-2), L(3,-2), dan M(-5,4). Nilai  cos L\cos\ L dan  tan M\tan\ M  berturut-turut adalah ....

 35\frac{3}{5}  dan  34\frac{3}{4}  

 34\frac{3}{4}  dan  35\frac{3}{5}  

 34\frac{3}{4}  dan  43\frac{4}{3}  

 45\frac{4}{5}  dan  34\frac{3}{4}  

 45\frac{4}{5}  dan  43\frac{4}{3}  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diketahui  ΔABC\Delta ABC  siku-siku di C. Jika  sin B=p\sin\ B=p  , maka nilai  tanB=\tan B=  ....

 p1p2\frac{p}{\sqrt{1-p^2}}  

 11p2\frac{1}{\sqrt{1-p^2}}  

 1p21\frac{1}{\sqrt{p^2-1}}  

 pp21\frac{p}{\sqrt{p^2-1}}  

 1p2p\frac{\sqrt{1-p^2}}{p}  

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