Standard deviation from grouped frequency tables

$$\sigma^2\ =\ 5.6\ \ \ \sigma=39.7$$

$$\sigma^2\ =6.5\ \ \ \sigma=41.7$$

$$\sigma^2\ =\ 39.7\ \ \ \sigma=5.6$$

$$\sigma^2\ =\ 41.7\ \ \ \sigma=6.5$$

Term 1 students spent less time on homework than Term 2, but there was more variation in the number of hours spent on the homework.

Term 2 students spent less time on homework than Term 1, but there was more variation in the number of hours spent on the homework.

Term 1 students spent less time on homework than Term 2, but there was less variation in the number of hours spent on the homework.

Term 2 students spent less time on homework than Term 1, but there was less variation in the number of hours spent on the homework.

Sylvia is correct. Since the standard deviation and IQR for Term 2 students is higher, this means that students spent more time exercising, on average, than Term 1.

Sylvia is incorrect. The standard deviation and the IQR shows that there is greater variability in the amount of time exercising for Term 2 students compared to Term 1, but it does not tell us that the group spent more time exercising than Term 1.

True

False

The average test score is higher for period 5, but the data is more spread out.

The average test score is higher for period 1, but the data is more spread out.

The average test score is higher for period 5, and the data is more consistent (closer to the mean) than period 1.

The average test score is higher for period 1, and the data is more consistent (closer to the mean) than period 5.

Company A

Company B

True

False