Unit 1 Review: The Real Numbers Quiz

Authored by FRANCES CAFFERTY

Mathematics

9th Grade

CCSS covered

Used 3+ times

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20 questions

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FILL IN THE BLANKS QUESTION

3 mins • 1 pt

$-6\cdot-8=$

(a)

Tags

CCSS.7.NS.A.2A

CCSS.7.NS.A.2B

FILL IN THE BLANKS QUESTION

3 mins • 1 pt

$-12-\left(-19\right)=$

(a)

Tags

CCSS.7.NS.A.1C

FILL IN THE BLANKS QUESTION

3 mins • 1 pt

$\left|-4-5\right|=$

(a)

Tags

CCSS.6.NS.C.7C

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

The absolute value of any number is________________.

Always Positive

Sometimes Positive

Never Positive

Tags

CCSS.6.NS.C.7C

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

$+\left(-\right)$ can be rewritten as:

$+$

$-$

$-\left(+\right)$

nothing else

Tags

CCSS.7.NS.A.1B

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

$-\left(-\right)$ can be rewritten as

$+$

$-$

neither

Tags

CCSS.7.NS.A.1B

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Write $\frac{3}{8}$ as a percent.

0.375%

3.75%

37.5%

3.8%

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Write $0.\overline{6}$ as a fraction in simplest form.

$\frac{3}{5}$

$\frac{2}{3}$

$\frac{6}{10}$

$\frac{6}{9}$

Tags

CCSS.7.NS.A.2D

CCSS.8.NS.A.1

FILL IN THE BLANKS QUESTION

3 mins • 1 pt

$3\ \frac{5}{9}-\left(-1\ \frac{1}{6}\right)=$

(a)

Tags

CCSS.7.NS.A.1C

10.

FILL IN THE BLANKS QUESTION

3 mins • 1 pt

$2\ \frac{1}{2}\div1\ \frac{3}{10}=$

(a)

Tags

CCSS.6.NS.A.1

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Unit 1 Review: The Real Numbers

−6⋅−8=-6\cdot-8=−6⋅−8= (a)

−12−(−19)=-12-\left(-19\right)=−12−(−19)= (a)

∣−4−5∣=\left|-4-5\right|=∣−4−5∣= (a)

The absolute value of any number is________________.

+(−)+\left(-\right)+(−) can be rewritten as:

−(−)-\left(-\right)−(−) can be rewritten as

Write 38\frac{3}{8}83​ as a percent.

Write 0.6‾0.\overline{6}0.6 as a fraction in simplest form.

3 59−(−1 16)=3\ \frac{5}{9}-\left(-1\ \frac{1}{6}\right)=3 95​−(−1 61​)= (a)

2 12÷1 310=2\ \frac{1}{2}\div1\ \frac{3}{10}=2 21​÷1 103​= (a)

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$-6\cdot-8=$

(a)

$-12-\left(-19\right)=$

(a)

$\left|-4-5\right|=$

(a)

$+\left(-\right)$ can be rewritten as:

$-\left(-\right)$ can be rewritten as

Write $\frac{3}{8}$ as a percent.

Write $0.\overline{6}$ as a fraction in simplest form.

$3\ \frac{5}{9}-\left(-1\ \frac{1}{6}\right)=$

(a)

$2\ \frac{1}{2}\div1\ \frac{3}{10}=$

(a)