Unit 5 Test Remediation
Quiz
•
Biology
•
9th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Alicia Lisee
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11 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Mei started feeling sick at school and the school nurse called her mom and suggested that they come by the clinic. Mei tested positive for the Influenza virus. She will need to allow her body to fight off the infection. In order to fight it, she would need to make antibodies, which are proteins. Which of the following describes the proper steps needed for Mei's cells to make these influenza antibodies?
Tags
NGSS.HS-LS1-1
NGSS.HS-LS1-6
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In a model of a DNA molecule created by students Hannah and Rohan, there are four parts labeled below. What can be inferred about the bonds between 1 and 2 versus the bonds between 3 and 4?
The bonds between 3 and 4 are weaker because they are held by hydrogen bonds
The bonds between 1 and 2 are weaker because they are held by covalent bonds
The bonds between 1 and 2 are stronger because they are held by hydrogen bonds
The bonds between 3 and 4 are stronger because they are held by covalent bonds
Tags
NGSS.HS-LS1-1
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In a recent biology project, David, Aria, and Hannah were analyzing the DNA of several organisms. They noticed some values were missing from their data table. According to Chargaff’s rule, if they were to determine the amount of guanine bases in chicken DNA, what percentage should it be?
29%
20%
21%
13%
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Fill in the blanks with the correct set of words below: In a high school biology class, Henry and Nora are learning how DNA replicates itself. They learn that the nitrogen bases of DNA, T-A and C-G, act as a template in building new DNA molecules during replication. But before replication can begin, an enzyme called ________ must _____________, starting at the replication origin.
DNA primase; split open the DNA
DNA polymerase; match nitrogen bases
helicase; split open the DNA
ligase; insert the correct nitrogen bases
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Maya is conducting an experiment in her biology class to extract DNA from a sample of bacteria collected from a local pond. After several steps, she obtains a preparation that contains only four types of molecules. Based on the characteristics listed in her lab notebook, molecule 2 would most likely be which type of molecule?
DNA
RNA
carbohydrate
protein
Tags
NGSS.HS-LS1-1
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
During a high school science project, Nora and Noah were examining the DNA segment of a fruit fly. They noticed a mutation similar to the one described here. What type of mutation has occurred? If this DNA molecule proceeds to transcription and translation, explain the impact of this mutation on the production of a protein?
This is a point mutation, resulting from the addition of one nitrogen base. This strand can no longer be used for transcription or translation due to its mutation.
This is a frameshift mutation, resulting from the substitution of one nitrogen base. If this strand of DNA is used for transcription, it will result in all of the amino acids being placed incorrectly in the protein.
This is a frameshift mutation, resulting from the addition of one nitrogen base. This strand can no longer be used for transcription or translation due to its mutation. If this strand of DNA is used for transcription, it will affect the coding of multiple amino acids, causing an incorrect protein to be assembled.
This is a point mutation, resulting from the substitution of one nitrogen base. If this strand of DNA is used for transcription, it will affect the coding of ONE amino acid, resulting in placing the correct amino acid in the protein, placing the wrong amino acid in the protein, or coding for the protein to stop building.
Tags
NGSS.HS-LS1-1
NGSS.HS-LS3-2
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In a biology class, William is asked to organize a list of genetic components from smallest to largest: 1. Chromosome 2. DNA nucleotide 3. Codon 4. Gene
1-2-4-3
2-3-4-1
3-4-2-1
4-3-2-1
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